|r+3| = (r+3) when r ≥ -3 so for r ≥ -3
r + 3 ≥ 7
r ≥ 4
|r+3| = -(r+3) when r < -3 so for r < -3
-(r + 3) ≥ 7
r + 3 ≤ -7
r ≤ -10
The answer to this question is r ≤ -10, r ≥ 4
Answer:
The answer is B
Step-by-step explanation:
-53=8x+5
First you would subtract the 5 on both sides then you would end up with
-58=8x
then you would divide both sides by 8 and get 7.25 or 7 1/4
Answer:
y = 25
Step-by-step explanation:
Hope this helps!
#include
int main()
{
int num;
scanf("%d", &num);
printf("%d", num*num);
return 0;
}
