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2 years ago

6

A pizza is to be cut into halves. Each of these halves is to be cut into sevenths. What fraction of the pizza is each of the fin

al pieces?

1 answer:

Hitman42 [59]2 years ago

7 0

Answer: $\dfrac{1}{14}$

Step-by-step explanation:

Given, A pizza is to be cut into halves.

Since half is represented by $\dfrac12$ .

So each piece is now $\dfrac12$ of the original.

if each of these halves is to be cut into sevenths, then the fraction of final pieces would be: $\dfrac{1}{2}\times\dfrac{1}{7}=\dfrac{1}{14}$ or we can say each half is divides into 7 pieces since there are two halves, so there will be 2 x 7 = 14 peices.

And the fraction of the pizza is each of the final pieces = $\dfrac{1}{14}$ .

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Please, I need help in this ??

nignag [31]

Answer:

$\int\frac{x^{4}}{x^{4} -1}dx = x + \frac{1}{4} ln(x-1) - \frac{1}{4} ln(x+1)-\frac{1}{2} arctanx + c$

Step-by-step explanation:

$\int\frac{x^{4}}{x^{4} -1}dx$

Adding and Subtracting 1 to the Numerator

$\int\frac{x^{4} - 1 + 1}{x^{4} -1}dx$

Dividing Numerator seperately by $x^{4} - 1$

$\int 1 + \frac{1}{x^{4}-1 }\, dx$

Here integral of 1 is x +c1 (where c1 is constant of integration

$x + c1 + \int\frac{1}{(x-1)(x+1)(x^{2}+1)}\, dx$ ----------------------------------(1)

We apply method of partial fractions to perform the integral

$\frac{1}{(x-1)(x+1)(x^{2}+1)}$ = $\frac{A}{x-1} + \frac{B}{x+1} + \frac{C}{x^{2} + 1}$ ------------------------------------------(2)

$\frac{1}{(x-1)(x+1)(x^{2}+1)} = \frac{A(x+1)(x^{2} +1) + B(x-1)(x^{2} +1) + C(x-1)(x+1)}{(x-1)(x+1)(x^{2} +1)}$

1 = $A(x+1)(x^{2} +1) + B(x-1)(x^{2} +1) + C(x-1)(x+1)$ -------------------------(3)

Substitute x= 1 , -1 , i in equation (3)

1 = A(1+1)(1+1)

A = $\frac{1}{4}$

1 = B(-1-1)(1+1)

B = $-\frac{1}{4}$

1 = C(i-1)(i+1)

C = $-\frac{1}{2}$

Substituting A, B, C in equation (2)

$\int\frac{x^{4}}{x^{4} -1}dx$ = $\int\frac{1}{4(x-1)} - \frac{1}{4(x+1)} -\frac{1}{2(x^{2}+1) }$

On integration

Here $\int \frac{1}{x}dx = lnx and \int\frac{1}{x^{2}+1 } dx = arctanx$

$\int\frac{x^{4}}{x^{4} -1}dx$ = $\frac{1}{4} ln(x-1)$ - $\frac{1}{4} ln(x+1)$ - $\frac{1}{2} arctanx$ + c2---------------------------------------(4)

Substitute equation (4) back in equation (1) we get

$x + c1 + \frac{1}{4} ln(x-1) - \frac{1}{4} ln(x+1) - \frac{1}{2} arctanx + c2$

Here c1 + c2 can be added to another and written as c

Therefore,

$\int\frac{x^{4}}{x^{4} -1}dx = x + \frac{1}{4} ln(x-1) - \frac{1}{4} ln(x+1)-\frac{1}{2} arctanx + c$

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3 years ago

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dmitriy555 [2]

Answer:

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Step-by-step explanation:

bottom rectangle area = 16 x 10 = 160

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160+ 12 +12= 184

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erastova [34]

AWNSER: B or 54

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asambeis [7]

Answer:

Step-by-step explanation:

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2 years ago

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mr Goodwill [35]

Answer: The tip left for the servers was $14.80

Step-by-step explanation:

Hi, to answer this question we have to analyze the information given:

<em>Total cost of the food (before tax) = $82.25 </em>
<em>Tip = 18% of the amount before the tax </em>

So, to calculate the tip we have to multiply the cost of the food before tax ($82.25) by the 0.18 (percentage in decimal form, 18/100= 0.18).

Mathematically speaking:

82.25 x 0.18 = $14.80

The tip left for the servers was $14.80

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