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2 years ago

Find the gcf and lcm of 10and15

Mathematics

1 answer:

Murrr4er [49]2 years ago

3 0

The greatest common factor of 10 is 10 and the least common factor of 15 is 15
Hope I helped!!!!!

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Click here What is the average rate of change for this exponential function for the interval from x=2 to x = 4? 15 10 -5 5 10 O

Triss [41]

Answer:

c. 6

Step-by-step explanation:

Given

See attachment for graph

Required

Average rate of change

This is calculated as:

$Rate = \frac{f(b) - f(a)}{b - a}$

Where

$(a,b) = (2,4)$

So, we have:

$Rate = \frac{f(4) - f(2)}{4 - 2}$

$Rate = \frac{f(4) - f(2)}{2}$

Using the attached graph, we have:

$f(2) = 4$

$f(4) = 16$

So, we have:

$Rate = \frac{16- 4}{2}$

$Rate = \frac{12}{2}$

$Rate = 6$

4 0

2 years ago

7th grade math please help me will give brainliest

Alecsey [184]

Answer: 67.27

Step-by-step explanation:

7.1 x 7.1 for the square = 50.41

7.1 divided by 2 = 3.55

3.55 x 4.75= 16.86

Normally here you would divide by 2, but you don’t need two because there is 2 triangles that are the same

Add the 50.41 and the 16.86 and you have your answer!

8 0

2 years ago

Read 2 more answers

PLEASE HELP FAST WILL MARK BRAINLIEST!!!!!!

puteri [66]

Answer: the second one

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

(8b+12)+(3n+6)+(9b-4)

Bas_tet [7]

Answer:

17b+3n+14

Step-by-step explanation:

no any step

okk

finished

5 0

2 years ago

Read 2 more answers

A recent study suggested that 81% of senior citizens take at least one prescription medication. Amelia is a nurse at a large hos

Lady_Fox [76]

Null hypothesis: $p = 0.81$

Alternative hypothesis: $p \ne 0.81$

The null is based on a recent study that 81% of the population (in this case senior citizens) takes at least one medication. The alternative hypothesis is basically the flip of the claim made in the null.

If Amelia wanted to know if the percentage was less than 81%, then the alternative would be p < 0.81

If Amelia wanted to know if the percentage was larger than 81%, then the alternative would be p > 0.81

However, she wants to know if the percentage is 81%.

5 0

2 years ago