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damaskus [11]
3 years ago
13

Need help how to solve this

Mathematics
2 answers:
andrew-mc [135]3 years ago
4 0

4n-9=-9

+9 +9=0

4n=0

n=0

kow [346]3 years ago
3 0

x=0 because 0-9 = -9

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An oil well produces 172 gallons of oil each day. A standard oil barrel holds 42 gallons of oil. Abot how many barrels of oil wi
Mariulka [41]
The oil well will produce about 4 barrels of oil a day.
5 0
3 years ago
4 people can stay at a hotel for a week for 42£. Find the hotel cost bill for 3
satela [25.4K]

Answer:

31.5

Step-by-step explanation:

divide 42 by 4 you would get 10.5, then multiple 10.5 by 3 and you would get 31.5 thats the answer

4 0
3 years ago
The number of people arriving for treatment at an emergency room can be modeled by a Poisson Distribution with a rate parameter
AlekseyPX

Answer:

a) 0.052 = 5.2% probability that exactly three arrivals occur during a particular hour

b) 0.971 = 97.1% probability that at least three people arrive during a particular hour

c) 5.25 people are expected to arrive during a 45-min period

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Poisson Distribution with a rate parameter of seven per hour.

This means that \mu = 7

(a) What is the probability that exactly three arrivals occur during a particular hour?

This is P(X = 3).

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 3) = \frac{e^{-7}*7^{3}}{(3)!} = 0.052

0.052 = 5.2% probability that exactly three arrivals occur during a particular hour.

(b) What is the probability that at least three people arrive during a particular hour? (Round your answer to three decimal places.)

Either less than three people arrive, or at least three does. The sum of the probabilities of these events is 1. So

P(X < 3) + P(X \geq 3) = 1

We want P(X \geq 3), which is

P(X \geq 3) = 1 - P(X < 3)

In which

P(X \geq 3) = P(X = 0) + P(X = 1) + P(X = 2)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-7}*7^{0}}{(0)!} = 0.001

P(X = 1) = \frac{e^{-7}*7^{1}}{(1)!} = 0.006

P(X = 2) = \frac{e^{-7}*7^{2}}{(2)!} = 0.022

So

P(X \geq 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.001 + 0.006 + 0.022 + 0.029

P(X \geq 3) = 1 - P(X < 3) = 1 - 0.029 = 0.971

0.971 = 97.1% probability that at least three people arrive during a particular hour

(c) How many people do you expect to arrive during a 45-min period?

During an hour(60 minutes), 7 people are expected to arrive. So, using proportions:

\frac{45*7}{60} = \frac{3*7}{4} = \frac{21}{4} = 5.25

5.25 people are expected to arrive during a 45-min period

5 0
3 years ago
Write the ratio of apples to oranges in simplest form please explain. Thanks
Nadya [2.5K]
There are 6 apples and 2 oranges.
So the ratio of apples to oranges would be 6:2.
However this can be simplified, because these number have a common factor, which is 2. So you divide 2 by 2, and 6 by 2, and get 1 and 3. So the ratio of apples to oranges in simplified form is 1:3. Hope this explains it :)
7 0
3 years ago
Read 2 more answers
I NEED THE ANSWER TO THIS ASAP FOR A TEST PLEASE!!!!!!!!
Varvara68 [4.7K]

Answer:

192

Step-by-step explanation:

you really should do your own test

A = lwh

A = 6 x 4 x 5 + 3

A = 6 x 4 x 8

A = 192

7 0
3 years ago
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