Given the following group of numbers, 8, 2, 9,4, 2, 7, 8, 0, 4, 1, which of the following
2 answers:
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Answer:
68.1 units²
Step-by-step explanation:
Start by finding the area of the rectangle...
Then, find the area of the semicircle...
Now, add the two to get...
54+14.1=68.1
Using the sinusoidal function, it is found that the temperature will be below 0ºC between May and August.
<h3>What is a Sinusoidal function?</h3>- A sinusoidal function is a function that depends on a trigonometric function, having peaks according to the period and amplitude given by this function.
The function for the average monthly temperature, in m months after January, is given by:
Working with elementary angles, we have that:
From this, we have that it becomes negative after March, and positive before September, removing the middle two options.
Now, we have to test for April and May, that is, m = 4 and m = 5, hence:
Negative only in May, hence the temperature will be below 0ºC between May and August.
To learn more about sinusoidal function, you can take a look at brainly.com/question/18055768
<h3>Answer: 40</h3>
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Explanation:
JQ is longer than QN. We can see this visually, but the rule for something like this is the segment from the vertex to the centroid is longer compared to the segment that spans from the centroid to the midpoint.
See the diagram below.
The ratio of these two lengths is 2:1, meaning that JQ is twice as long compared to QN. This is one property of the segments that form when we construct the centroid (recall that the centroid is the intersection of the medians)
We know that JN = 60
Let x = JQ and y = QN
The ratio of x to y is x/y and this is 2/1
x/y = 2/1
1*x = y*2
x = 2y
Now use the segment addition postulate
JQ + QN = JN
x + y = 60
2y + y = 60
3y = 60
y = 60/3
y = 20
QN = 20
JQ = 2*y = 2*QN = 2*20 = 40
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We have
JQ = 40 and QN = 20
We see that JQ is twice as larger as QN and that JQ + QN is equal to 60.