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My name is Ann [436]
3 years ago
13

2x+8y=54 x+9y=67 Solve the system by subtitution

Mathematics
1 answer:
Kisachek [45]3 years ago
3 0

Step-by-step explanation:

2x +8y = 54

x + 9y = 67

x = 67 - 9y

2(67-9y) + 8y = 54

434 - 18y + 8y = 54

434 - 10y = 54

10y = 54 - 434

10y = -380

y = -38

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2 years ago
Write 2.04 × 10 ⁴ as an ordinary number
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Answer:

20400

Step-by-step explanation:

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3.27525 in expanded form
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Read 2 more answers
Samples of 20 parts from a metal punching process are selected every hour. Typically, 1% of the parts require rework. Let X deno
Roman55 [17]

Answer:

a) P(X>np+3\sqrt{np(1-p)}=0.017

b) P(x>1)=0.190

c) P(Y>1)=0.651

Step-by-step explanation:

This a binomial experiment where success is denoted by parts that need rework.

X ∼ B(n, p); n = 20; p = 0.01

The expected value of X is: E(X) = np =20×0.01= 0.2

The variance is: Var(X) = np(1 − p) = 0.2 × 0.99 = 0.198,

The standard deviation SD(X)= \sqrt{0.198} ≈ 0.445

a) P(X>np+3\sqrt{np(1-p)}=P(X>0.2+3×0.445)=P(X>1.535)=P(X≥2)

Probability function is given by:

\frac{n!}{x!(n-x)!} *p^x*(1-p)^{(n-x)}

P(X≥2)=1-P(X<2)=1-P(X=1)-P(X=0)= 1 - \frac{20!}{1!(20-1)!} *(0.01)^{1}*(1-0.01)^{(20-1)}-\frac{20!}{0!(20-0)!} *(0.01)^{0}*(1-0.01)^{(20-0)}

P(X≥2)=1-0.165-0.818=0.017

b) p=0.04

P(x>1)=P(x≥2)= 1 - P(x=1) - P(x=0)= 1 - \frac{20!}{0!(20-1)!} *(0.04)^{1}*(1-0.04)^{(20-1)} - \frac{20!}{0!(20-0)!} *(0.04)^{0}*(1-0.04)^{(20-0)}

P(x>1)= 1 - 0.368 - 0.442=0.190

c) In this case we consider p=0.19 (Probability that X exceeds 1)

In this experiment Y is the number of hours and n= 5 hours.

Then, we check the probability in each hour:

P(Y>1)=1- P(Y=0)

P(Y=0)=\frac{5!}{0!(5-0)!} *(0.19)^{0}*(1-0.19)^{(5-0)}=0.349

P(Y>1)=1-0.349=0.651

3 0
3 years ago
Y equals negative X squared +10 X -26
Pani-rosa [81]

Answer:

Step-by-step explanation:

y=(x+5)2−1

Use the vertex form,

y=a(x−h)2+k, to determine the values of a, h, and .a=1h=−5k=−1Find the vertex(h,k(−5,−1)

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3 years ago
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