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Veronika [31]
3 years ago
7

How to write k2o as a lewis dot structure and steps

Chemistry
1 answer:
DiKsa [7]3 years ago
8 0
First you have to do the cofiguration  électronique then determine l électron of valence if their is one spin make(.) and if thier two spin put(

sorry about my english.
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What subatomic particle determines how an element reacts with another element?
Amanda [17]
Hello my friend,
No. of valence electron determine the reaction between elements.
hope it helps☺☺
4 0
4 years ago
The energy of any one-electron species in its nth state (n = principal quantum number) is given by E = –BZ2 /n2 where Z is the c
Ivahew [28]

Explanation:

(a) The given data is as follows.

            B = 2.180 \times 10^{-18} J

            Z = 4 for Be

Now, for the first excited state n_{f} = 2; and n_{i} = \infinity if it is ionized.

Therefore, ionization energy will be calculated as follows.

         I.E = \frac{-Bz^{2}}{\infinity^{2}} - (\frac{-2.180 \times 10^{-18} J /times (4)^{2}}{(2)^{2}})

              = 8.72 \times 10^{-18} J

Converting this energy into kJ/mol as follows.

           8.72 \times 10^{-18} J \times 6.02 \times 10^{23} mol  

           = 5249 kJ/mol

Therefore, the ionization energy of the Be^{3+} ion in its first excited state in kilojoules per mole is 5249 kJ/mol.

(b) Change in ionization energy is as follows.

         \Delta E = -Bz^{2}(\frac{1}{(4)^{2}} - {1}{(2)^{2}}) = \frac{hc}{\lambda}

   \frac{hc}{\lambda} = 0.1875 \times 2.180 \times 10^{-18} J \times (4)^{2}                

        \lambda = \frac{6.626 \times 10^{-34} \times 2.998 \times 10^{8} m/s}{0.1875 \times 2.180 \times 10^{-18} J \times 16}

                     = 303.7 \times 10^{-10} m

or,                 = 303.7^{o}A

Therefore, wavelength of light given off from the Be^{3+} ion by electrons dropping from the fourth (n = 4) to the second (n = 2) energy levels 303.7^{o}A.

5 0
3 years ago
a sample of ammonia liberates 5.66 kj of heat as it solidifies at its melting point . what is the mass of the sample?
Reil [10]
The correct answer for the question that is being presented above is this one: "<span>16.728 g."</span>

Given that 
ΔHsolid = -5.66 kJ/mol.
This means that 5.66 kJ of heat is released when 1 mole of NH3 solidifies 

When 5.57 kJ of heat is released
amount of NH3 solidifies = 5.57/5.66 = 0.984 moles 

<span>molar mass of NH3 = 17 g/mole </span>
<span>1 mole of NH3 = 17 g </span>
So, 0.984 moles of NH3 = 17 X 0.984 = 16.728 g
7 0
3 years ago
I am a metalloid. I am in the nitrogen family and row 4. I have an atomic mass of 74.92. I can be used as a poison. Who am I?
musickatia [10]
Arsenic

Arsenic has an atomic mass of 74.92, is a well known poison, and a metalloid.
6 0
3 years ago
Read 2 more answers
What is the proper way of collection, preservation and transition of hair?​
Murrr4er [49]
An investigator can collect hairs they observe visually (with tweezers or by hand), and they can also use clear tape to lift non-visible hair from a variety of surfaces, such as clothing. Other methods of hair sample collection include combing and clipping methods.
7 0
3 years ago
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