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3 years ago

I am a metalloid. I am in the nitrogen family and row 4. I have an atomic mass of 74.92. I can be used as a poison. Who am I?

Chemistry

2 answers:

musickatia [10]3 years ago

6 0

Arsenic

Arsenic has an atomic mass of 74.92, is a well known poison, and a metalloid.

bulgar [2K]3 years ago

4 0

Answer:

As – Arsenic

Explanation:

Let's break this down step by step. Make sure you have a periodic table to reference.

"I am a metalloid" – We will be looking towards the right side of the periodic table. The possible choices are boron (B), silicon (Si), germanium (Ge), arsenic (As), antimony (Sb), tellurium (Te), and astatine (At).

"I am in the nitrogen family" – Families are elements grouped by <em>columns</em>. The nitrogen family is group 15. The possible choices are now arsenic (As) and antimony (Sb).

"and row 4" – Counting from the very top (don't forget row 1 of hydrogen and helium), we can see that arsenic (As) is in the 4th row.

"I have an atomic mass of 74.92" – Arsenic (As) does have an atomic mass of 74.92, which confirms our answer.

Hope this helps!

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Obsidian is a volcanic glass that forms when lava cools very quickly and consists of a solid mass of glass through and through.

Alecsey [184]

Answer:

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Explanation:

Obsidian originates naturally and is formed by igneous rock.

When felsic larva comes out from the volcano,it rapidly cools down and thus form obsidian.It is pure black in color but some times color differ due to presence of some impurities.

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3 years ago

Which of the slightly soluble salts below will be more soluble in acidic solution than in pure water?

AlexFokin [52]

Answer:

h. both Mg(OH)₂ and CaCO₃

Explanation:

Let's consider the solution of Mg(OH)₂ according to the following equation:

Mg(OH)₂(s) ⇄ Mg²⁺(aq) + 2 OH⁻(aq)

In acidic solution, OH⁻ reacts with H⁺ to form H₂O.

OH⁻(aq) + H⁺(aq) ⇄ H₂O(l)

According to Le Chatelier's principle, since [OH⁻] decreases, the solution of Mg(OH)₂(s) shifts toward the right, increasing its solubility.

Let's consider the solution of CaCO₃ according to the following equation:

CaCO₃(s) ⇄ Ca²⁺(aq) + CO₃²⁻(aq)

In acidic solution, CO₃²⁻ reacts with H⁺ to form HCO₃⁻.

CO₃²⁻(aq) + H⁺(aq) ⇄ HCO₃⁻(aq)

According to Le Chatelier's principle, since [CO₃²⁻] decreases, the solution of CaCO₃(s) shifts toward the right, increasing its solubility.

Let's consider the solution of AgCl according to the following equation:

AgCl(s) ⇄ Ag⁺(aq) + Cl⁻(aq)

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Rina8888 [55]

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3 years ago

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The problem the answer u are looking for a

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Mercury can be obtained by reacting mercury(I) sulfide with calcium oxide. How many grams of calcium oxide are needed to produce

OLga [1]

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3 years ago