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Sholpan [36]
3 years ago
15

What is the pOH of a 0.025 M [H+] solution? A.0.94 B.1.60 C.12.40 D.13.06

Chemistry
1 answer:
Greeley [361]3 years ago
6 0

Answer:

option C= 12.40

Explanation:

Formula:

pH + pOH = 14

First of all we will calculate the pH.

pH = - log [H⁺]

pH = - log [0.025]

pH = - (-1.6)

pH = 1.6

Now we will put the values in formula,

pH + pOH = 14

pOH = 14-pH

pOH = 14 -1.6

pOH = 12.4

The pOH of solution is 12.4.

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A phosphate buffer is involved in the formation of urine. The developing urine contains H2PO4 and HPO42- in the same concentrati
Katen [24]

Answer:

The ionization equation is

H_{2}PO_{4}^{-}  +H_{2}O ⇄HPO_{4}^{-2}  +H_{3}O^{+} (1)

Explanation:

The ionization equation is

H_{2}PO_{4}^{-}  +H_{2}O ⇄HPO_{4}^{-2}  +H_{3}O^{+} (1)

As the Bronsted definition sais, an acid is a substance with the ability to give protons thus, H2PO4 is the acid and HPO42- is the conjugate base.

The Ka expression is the ratio between the concentration of products and reactants of the equilibrium reaction so,

Ka = \frac{[HPO_{4}^{-2}] [H_{3}O^{+}]}{[H_{2}PO_{4}^{-}] [H_{2}O]} = 6.2x10^{-8}

The pKa is

-Log (Ka) = -Log (6.2x10^{-8}) = 7.2

The pKa of H2CO3 is 6,35, thus this a stronger acid than H2PO4. The higher the pKa of an acid greater the capacity to donate protons.

In the body H2CO3 is a more optimal buffer for regulating pH due to the combination of the two acid-base equilibriums and the two pKa.

If the urine is acidified, according to Le Chatlier's Principle the equilibrium (1)  moves to the left neutralizing the excess proton concentration.

3 0
3 years ago
How many electrons are in an atom that has 25 protons and has an ion charge of negative 3
olya-2409 [2.1K]

Answer:

7

Explanation:

3x6=18 leavig 7 behind

6 0
3 years ago
What is the molecular weight of a monoprotic carboxylic acid if 11.20 mL of 0.9635 M sodium hydroxide is required to titrate 1.2
Vlada [557]

Answer:

116.1 a.m.u.

It is not likely that RCOOH is the pentanoic acid

Explanation:

Let's consider the generic neutralization between NaOH and a monoprotic carboxylic acid.

RCOOH(aq) + NaOH(aq) ⇒ RCOONa(aq) + H₂O(l)

The molar ratio of RCOOH to NaOH is 1:1. The moles of RCOOH are:

11.20 \times 10^{-3}L.\frac{0.9635molNaOH}{1L}. \frac{1molRCOOH}{1molNaOH} =1.079 \times 10^{-2}molRCOOH

The molar mass of RCOOH is:

\frac{1.253g }{1.079 \times 10^{-2}mol } =116,1g/mol

Thus, the molecular weight is 116.1 a.m.u.

Pentanoic acid has the formula C₅H₁₀O₂ with a molecular weight of 102.1 a.m.u. So, it is not likely that RCOOH is the pentanoic acid.

4 0
3 years ago
Find the answer using dimentional analysis. A child requires a 5 ml dose of medicine each day. How many days would a gallon of t
vazorg [7]

Conversion factor, 1 gallon = 4546.09 ml

Volume of stock solution = 1 gallon or 4546.09 ml

Dose required by the child = 5 ml/day

The number of days a gallon of this medicine last,

4546.09 ml x 1  day/ 5 ml = 909.218 days

Therefore, 1 gallon would last 909 days.

4 0
3 years ago
How is a compound formed differently than a mixture, and how can each be broken down into their original substances?
saveliy_v [14]

Answer: Pure substances are further broken down into elements and compounds. Mixtures are physically combined structures that can be separated into their original components. A mixture is composed of different types of atoms or molecules that are not chemically bonded.

Explanation:

5 0
3 years ago
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