Sum of aritmetic sqeuqnece is
(n/2)(a1+an)
a1=first term
an=nth term
n=how many terms
so we gots
a1=3(1)-4=-1
a18=50
n=18
(18/2)(-1+50)
(9)(49)
441
other one
a1(1-r^(n+1))/(1-r)
2(1-2^(15+1))/(1-(1/4))
about 2 and 2/3, so closer to 3
Answer:
6 * ![\sqrt[3]{x}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D)
Step-by-step explanation:
6 x^1/3
The 1 means inside to the power of 1 and the 3 means to the cubed root
6 * ![\sqrt[3]{x}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D)
It’ll be -5x - 24
you multiply the 5 by 4 and it’ll be 24, and put the x with the 5 and that’ll be your answer :)
For the above equation and given zeros of polynomial equation we have;
y=(x+2)(x-3)(x+4)
y=(x^2+2x-3x-6)(x+4)
y=(x^2-x-6)(x+4)
y=(x^3-x^2-6x+4x^2-4x-24)
y=x^3+3x^2-10x-24
Therefore our answer is 3
Hope this helps. Any questions please just ask. Thank you.