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3 years ago

Which planet has a fierce hurricane-like storm that is several times the size of earth?

Chemistry

2 answers:

hichkok12 [17]3 years ago

5 0

The planet with a hurricane-like storm several times the size of Earth is Jupiter.

LenKa [72]3 years ago

3 0

Jupiter is definitely the planet

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Answer and work for this problem

MArishka [77]

We can write the balanced equation for the synthesis reaction as
H2(g) + Cl2(g) → 2HCl(g)

We use the molar masses of hydrogen chloride gas HCl and hydrogen gas H2 to calculate for the mass of hydrogen gas H2 needed:
mass of H2 = 146.4 g HCl *(1 mol HCl / 36.46 g HCl) * (1 mol H2 / 2 mol HCl) *
(2.02 g H2 / 1 mol H2)
= 4.056 g H2

We also use the molar masses of hydrogen chloride gas HCl and chlorine gas CL2 to calculate for the mass of hydrogen gas H2:
mass of CL2 = 146.4 g HCl *(1 mol HCl / 36.46 g HCl) * (1 mol Cl2 / 2 mol HCl) *
(70.91 g Cl2 / 1 mol Cl2)
= 142.4 g Cl2

Therefore, we need 4.056 grams of hydrogen gas and 142.4 grams of chlorine gas to produce 146.4 grams of hydrogen chloride gas.

6 0

3 years ago

Several constructive processes helped build mountains on Earth. All BUT one of these is a way mountains can be built. That is A)

Naddik [55]

It is landslides i got it right on the test

7 0

3 years ago

What is the ph of a peach with a [ –oh] = 3.2 × 10 –11 m?

iogann1982 [59]

H+= 10^-14 / [OH-1 = 3.125 * 10^-4 M
pH=-log(H+) = 3.505

Just round it down and your answer = 3.5

3 0

2 years ago

A reaction was performed in which 4.0 g of cyclohexanol was reacted with an acid catalyst to obtain 2.8 g of cyclohexene. calcul

ioda

Answer:

%age Yield = 85.36 %

Solution:

The Balance Chemical Reaction is as follow,

C₆H₁₂O + Acid Catalyst → C₆H₁₀ + Acid Catalyst + H₂O

According to Equation ,

100 g (1 mole) C₆H₁₂O produces = 82 g (1 moles) of C₆H₁₀

So,

4.0 g of C₆H₁₂O will produce = X g of C₆H₁₀

Solving for X,

X = (4.0 g × 82 g) ÷ 100 g

X = 3.28 g of C₆H₁₀ (Theoretical Yield)

As we know,

%age Yield = (Actual Yield ÷ Theoretical Yield) × 100

%age Yield = (2.8 g ÷ 3.28 g) × 100

%age Yield = 85.36 %

5 0

2 years ago

what mass of sodium fluoride (FW=42.0 g/mol) must be added to 3.50 x 10^2 mL of water to give a solution with pH = 8.40?

MaRussiya [10]

Answer:

Explanation:

Sodium fluoride, being a salt, dissolves in water completely producing F ⁻ ions. Now F⁻ is the conjugate base of the weak acid HF, so in water we will have the following equilibrium:

F⁻ + H₂O ⇆ HF + OH⁻

Given this equilibrium, we need to calculate Kb from the Ka for HF, the [ OH ⁻] from the given pH, and finally the mass needed to produce that OH⁻ concentration.

The equilibrium constant, Kb , can be calculated from Kw = Ka x Kb, where Kw = 10⁻¹⁴ and Ka for HF is 6.6 x 10⁻⁴ from reference tables.

Kb = 10⁻¹⁴ / 6.6 x 10⁻⁴ = 1.5 x 10⁻¹¹

pH + pOH = 14 ⇒ pOH = 14 - 8.40 = 5.60

[ OH⁻ ] = 10^-5.60 = 2.51 x 10⁻⁶

Now we have all the information :

F⁻ HF OH⁻

Equilibrium X 2.51 x 10⁻⁶ 2.51 x 10⁻⁶

(2.51 x 10⁻⁶)² / X = 1.5 x 10⁻¹¹ ⇒ X = (2.51 x 10⁻⁶)² / 1.5 x 10⁻¹¹

X = [ F⁻ ] = 0.41 M

For 350 mL ( 0.35 L ) we need to add:

0.41 mol HF/ 1 L * 0.35 L = 0.144 mol

and finally the mass will be:

0.144 mol NaF * 42.0 g/mol NaF = 6.03 g NaF

7 0

2 years ago