Valency- it means the combing capacity if an element.
<span> radical- it is an atom, molecule, or ion that has unpaired valence electrons or an open electron shell.
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Answer:
The answer to your question is Argon
Explanation:
Electron configuration given 1s² 2s² 2p⁶ 3s² 3p⁶
To find the element whose electron configuration is given, we can do it by two methods.
Number 1. Sum all the exponents the result will give you the atomic number of the element.
2 + 2 + 6 + 2 + 6 = 18
The element with an atomic number of 18 is Argon.
Number 2. Look at the last terms of the electronic configuration
3s² 3p⁶
Number three indicates that this element is in the third period in the periodic table.
Sum the exponents 2 + 6 = 8
Number 8 indicates that this element is the number 8 of that period without considering the transition elements.
The element with these characteristics is Argon.
Answer:
<h2>6426000 mg</h2>
Explanation:
The mass of a substance when given the density and volume can be found by using the formula
mass = Density × volume
From the question
63 mL = 63 cm³
We have
mass = 102 × 63 = 6426
But 1 g = 1000 mg
6426 g = 6426000 mg
We have the final answer as
<h3>6,426,000 mg</h3>
Hope this helps you
Answer: The molarity of solution is 0.231 M
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

where,
n = moles of solute
= volume of solution in L
Molar mass of
= 
moles of
= 
Now put all the given values in the formula of molality, we get


Therefore, the molarity of solution is 0.231 M
Answer:
3.676 L.
Explanation:
- We can use the general law of ideal gas: PV = nRT.
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in K.
- If n and P are constant, and have different values of V and T:
(V₁T₂) = (V₂T₁)
V₁ = 3.5 L, T₁ = 25°C + 273 = 298 K,
V₂ = ??? L, T₂ = 40°C + 273 = 313 K,
- Applying in the above equation
(V₁T₂) = (V₂T₁)
∴ V₂ = (V₁T₂)/(T₁) = (3.5 L)(313 K)/(298 K) = 3.676 L.