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ycow [4]
3 years ago
12

Help me please!!!!!!!!!!!!!!!

Chemistry
1 answer:
Alex787 [66]3 years ago
8 0

Answer:

2KBr + MgF₂ –> 2KF + MgBr₂

The coefficients are: 2, 1, 2, 1

Explanation:

KBr + MgF₂ –> KF + MgBr₂

The above equation can be balance as illustrated below:

KBr + MgF₂ –> KF + MgBr₂

There are 2 atoms of F on the left side and 1 atom on the right. It can be balance by writing 2 before KF as shown below:

KBr + MgF₂ –> 2KF + MgBr₂

There 2 atoms of K on the right side and 1 atom on the left side. It can be balance by writing 2 before KBr as shown below:

2KBr + MgF₂ –> 2KF + MgBr₂

Now, the equation is balanced.

The coefficients are: 2, 1, 2, 1

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What is the purpose of adding 0. 1% agar to the trypticase nitrate broth when conducting the nitrate reduction test?.
PilotLPTM [1.2K]

Agar is used to assist establish an anaerobic environment that promotes nitrate reduction.

Nitrate Reduction test:

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Learn more about the Nitrate reduction test with the help of the given link:

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5 0
1 year ago
Estimate the molar mass of a gas that effuses at 1.80 times the effusion rate of carbon dioxide. answer in units of g/mol.
Effectus [21]
From Grahams Law the rates of effusion of two gases are inversely proportional to the square roots of their molar masses at the same temperature and pressure.
Therefore; R1/R2 = √mm2/√mm1
The molecular mass of Carbon dioxide is 44 g
Hence;  1.8 = √(44/x
             3.24 = 44/x
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                   = 13.58 
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3 0
3 years ago
A balloon that had a volume of 3.50 L at 25.0°C is placed in a hot room at 40.0°C. If the pressure remains constant at 1.00 atm,
choli [55]

Answer:

3.676 L.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R  is the general gas constant,

T is the temperature of the gas in K.

If n and P are constant, and have different values of V and T:

(V₁T₂) = (V₂T₁)

Knowing that:

V₁ = 3.5 L, T₁ = 25°C + 273 = 298 K,

V₂ = ??? L, T₂ = 40°C + 273 = 313 K,

Applying in the above equation

(V₁T₂) = (V₂T₁)

∴ V₂ = (V₁T₂)/(T₁) = (3.5 L)(313 K)/(298 K) = 3.676 L.

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3 years ago
Which characteristic gives the most information about what kind of element
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Answer:

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