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olga_2 [115]
3 years ago
15

Suppose you have 4.0 L of helium in a flexible container (like a balloon) at a certain temperature and pressure. What will the v

olume of the helium be if the absolute temperature is halved and the pressure is doubled?
Chemistry
2 answers:
AleksandrR [38]3 years ago
5 0

Answer:

Volume of the helium will be 1.0L

Explanation:

To understand this question it is necessary to talk about 2 laws:

Charles's law that states: The volume of a given amount of gas held at constant pressure is directly proportional to absolute temperature.

Boyle's law that states: The volume of a given amount of gas held at constant temperature varies inversely with the applied pressure when the temperature and mass are constant.

Now, in the problem, if you have 4.0L of helium:

If the temperature is halved and the volume varies directly with temperature (Charles's law), the volume of helium will be 2.0L

Then, the pressure es doubled and as volume varies inversely with pressure (Boyle's law), the volume of helium will be halved, being 1.0L.

Thus, <em>volume of the helium will be 1.0L</em>

77julia77 [94]3 years ago
3 0

Answer:

When the temperature is halved and the pressure is doubled, the volume will be divided by 4. The new volume will be 1.0 L

Explanation:

Step 1: Data given

Volume of the balloon = 4.0 L

Suppose the pressure of helium gas = 100 atm

Suppose the temperature = 100 K

The absolute temperature is halved = 50 K

The pressure is doubled = 200 atm

Step 2: Calculate the new volume

(P1*V1)/T1 = (P2*V2)/T2

⇒with P1 = the initial pressure = 100 atm

⇒with V1 = the initial volume = 4.0 L

⇒with T1 = the initial temperature = 100 K

⇒with P2 = the doubled pressure = 200 atm

⇒with V2 = the new volume = TO BE DETERMINED

⇒with T2 = the halved temperautre = 50 K

(100 atm * 4.0 L) / 100 K = (200 atm * V2) / 50 K

V2 = (100 * 4 * 50 ) / (100*200)

V2 = 1 L

When the temperature is halved and the pressure is doubled, the volume will be divided by 4. The new volume will be 1.0 L

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Si desea preparar 300 gramos de una solución de azúcar en agua que tenga una concentración de 20% m/m en cuanto gramos de soluto
Digiron [165]

Answer:

m_{soluto}=60g

Explanation:

¡Hola!

En este caso, al considerar la unidad de concentración de porcentaje masa/masa, podemos escribir su fórmula como:

\%m/m=\frac{m_{soluto}}{m_{solucion}}*100\%

Podemos identificar la masa de soluto (azúcar) como la incógnita, y resolverla como se muestra a continuación:

m_{soluto}=\frac{\%m/m*m_{solucion}}{100\%}\\\\m_{soluto}=\frac{20\%*300g}{100\%}\\\\m_{soluto}=60g

¡Saludos!

5 0
3 years ago
The total volume of a soda can is 415 mL. Of this 415 mL, there is 60.0 mL of headspace(empty space aka volume) for the CO2 gas
almond37 [142]

Answer:

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Explanation:

6 0
2 years ago
Which equation represents a double replacement reaction?
AveGali [126]

Answer:

C) LiOH + HCl → LiCl + H₂O

General Formulas and Concepts:

<u>Chemistry - Reactions</u>

  • Synthesis Reactions: A + B → AB
  • Decomposition Reactions: AB → A + B
  • Single-Replacement Reactions: A + BC → AB + C
  • Double-Replacement Reactions: AB + CD → AD + BC

Explanation:

<u>Step 1: Define</u>

RxN A:   2Na + 2H₂O → 2NaOH + H₂

RxN B:   CaCO₃ → CaO + CO₂

RxN C:   LiOH + HCl → LiCl + H₂O

RxN D:   CH₄ + 2O₂ → CO₂ + 2H₂O

<u>Step 2: Identify</u>

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mr_godi [17]

Answer:8

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a.

Explanation:

7 0
2 years ago
If an ideal gas has a pressure of 2.97 atm, a temperature of 449 K, and has a volume of 58.35 L, how many miles of gas are in th
soldi70 [24.7K]
N = ?

T = 449 K

V = 58.35 L

P =2.97

R = 0.082

Use the clapeyron equation:

P x V = n x R x T

2.97 x 58.35 = n x 0.082 x 449

173.2995 = n x 36.818

n = 173.2995 / 36.818

n = 4.70 moles

hope this helps!



7 0
3 years ago
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