Answer: The required width of the park is 3 miles.
Step-by-step explanation: Given that a 5 mile jogging path diagonal divides a rectangular park in half and the park is 4 miles long.
We are to find the width of the park.
As shown in the attached figure below, the diagonal BD divides the rectangle ABCD into two equal parts,
where length DA = 5 miles, BD = 4 miles and AB = width = ?
Since each angle of a rectangle is right-angle, so triangle ABD will be a right-angled triangle.
Using Pythagoras theorem in triangle ABD, we have
Thus, the required width of the park is 3 miles.
Answer:
Sacramento is 8cm from San Francisco.
8cm in map = 91 miles
91/8 = 11.375
1cm in map = 11.375 miles
Sacramento is 7 cm away from Modesto.
7 · 11.375 = 79.625
The actual distance is 79.625 miles
You do 3x6 first to get 18.
You get 3-18+2.
Then you do 3-18 which is -15.
You get -15+2.
Then you do -15+2 which is -13.
It equals -13.
Answer:
the coordinates of the point of x and y is -1÷ 2 and -√3÷ 2
Step-by-step explanation:
The computation of the coordinates of the point is shown below:
The angle is
= 4π ÷ 3
The radius is 1 unit
Now
x = rcos
, and y = rsin
Now
x = 1cos(4π ÷ 3) = -1÷ 2
y = 1sin(4π ÷ 3) = -√3÷ 2
hence, the corordinates of the point of x and y is -1÷ 2 and -√3÷ 2
Answer:
Lease value
Step-by-step explanation:
The lease value may bed defined as an open market capital valuation of the parts of the subject or the subject that are to be leased in regards of the terms of the lease.
In the context, Lakiesha drives a company car whose value is $ 7,750 according to 15-b publication. The car was available for 200 days in a year. She drove the car for 4500 miles for her personal use and 21250 miles in total. The fuel is paid by the employer. So here the best method that will yield the lowest fringe benefit amount for her is the lease value method.
