We need to find the surface area and volume for each rectangular prism. Here are the formulas I'm going to plug each prism's measurements.
S.Area=2(lw+wh+lh)
Volume: lwh
Question 75:
Volume: 3×1×3=9 cm³
Surface Area= 2(3)+2(3)+2(9)=6+6+18=30 cm²
Question 76:
Volume: 6×2×5=60 ft.³
Surface Area: 2(12)+2(10)+2(30)=24+20+60=104 ft²
Question 77:
Volume: 4×2×6=48 m³
Surface Area: 2(8)+2(12)+2(24)=16+24+48=88 m²
Answer:
530.66 mm²
5.3066 cm²
Step-by-step explanation:
A = π·r²
= 3.14×(13mm)²
= 3.14×169mm²
= 530.66 mm²
= 5.3066 cm²
Answer:
16
Step-by-step explanation:
p=k√q
8=k√25
8=k5
k=8/5
p when q=100
p=8/5*√100
p=8/5*10
p=16
Answer:
y = 3sin2t/2 - 3cos2t/4t + C/t
Step-by-step explanation:
The differential equation y' + 1/t y = 3 cos(2t) is a first order differential equation in the form y'+p(t)y = q(t) with integrating factor I = e^∫p(t)dt
Comparing the standard form with the given differential equation.
p(t) = 1/t and q(t) = 3cos(2t)
I = e^∫1/tdt
I = e^ln(t)
I = t
The general solution for first a first order DE is expressed as;
y×I = ∫q(t)Idt + C where I is the integrating factor and C is the constant of integration.
yt = ∫t(3cos2t)dt
yt = 3∫t(cos2t)dt ...... 1
Integrating ∫t(cos2t)dt using integration by part.
Let u = t, dv = cos2tdt
du/dt = 1; du = dt
v = ∫(cos2t)dt
v = sin2t/2
∫t(cos2t)dt = t(sin2t/2) + ∫(sin2t)/2dt
= tsin2t/2 - cos2t/4 ..... 2
Substituting equation 2 into 1
yt = 3(tsin2t/2 - cos2t/4) + C
Divide through by t
y = 3sin2t/2 - 3cos2t/4t + C/t
Hence the general solution to the ODE is y = 3sin2t/2 - 3cos2t/4t + C/t
I think it is 1/3 but I am not sure. Sorry if wrong.
