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3 years ago

Solve each question using the quadratic formula? X2+4x+3=0

Mathematics

1 answer:

Sergeeva-Olga [200]3 years ago

8 0

x=−1 or x=−3 i think lol

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Evaluate the following at select the best answer 8 (3 exponent seven) minus (6 + 4) 2

photoshop1234 [79]

Answer:

17476

Step-by-step explanation:

8( $3^{7}$ )-(6+4)2

8(2187)-(10)2

17496-20

17476

3 0

2 years ago

Write down 6 numbers that have a median of 8, a mean of 9 and a range of 13

spayn [35]

Answer:

ummm i tried but.....

Step-by-step explanation:

5 0

2 years ago

I need help with this question

Novay_Z [31]

Answer:

$\frac{\sqrt{3} - 1}{2\sqrt{2}}$

$\frac{-(\sqrt{3} + 1)}{2\sqrt{2}}$

$- \frac{\sqrt{3} - 1}{\sqrt{3} + 1}$

Step-by-step explanation:

Given $\frac{11 \pi}{12} = \frac{3 \pi}{4} + \frac{\pi}{6}$

(A) $sin(\frac{11\pi}{12}) = sin (\frac{3 \pi}{4} + \frac{\pi}{6})$

We know that Sin(A + B) = SinA cosB + cosAsinB

Substituting in the above formula we get:

$sin (\frac{3\pi}{4} + \frac{\pi}{6}) = \frac{1}{\sqrt{2}} . \frac{\sqrt{3}}{2} + \frac{-1}{\sqrt{2}}. \frac{1}{2}$

$$ \implies \frac{1}{\sqrt{2}} (\frac{\sqrt{3} - 1}{2}) = \frac{\sqrt{3} - 1}{2\sqrt{2}}$

(B) Cos(A + B) = CosAcosB - SinASinB

$cos(\frac{11\pi}{12}) = cos(\frac{3\pi}{4} + \frac{\pi}{6}})$

$\implies \frac{-1}{\sqrt{2}}. \frac{\sqrt{3}}{2} - \frac{1}{\sqrt{2}} . \frac{1}{2}$

$\implies cos(\frac{11\pi}{12}) = cos(\frac{3\pi}{4} + \frac{\pi}{6})$

$$ = \frac{-(\sqrt{3} + 1)}{2\sqrt{2}}$

From the above obtained values this can be calculated and the value is $- \frac{\sqrt{3} - 1}{\sqrt{3} + 1}$ .

3 0

2 years ago

Y = 4x + 3 in slope line parallel

Gala2k [10]

Answer:

y=4x would be one

Step-by-step explanation:

I hope its right...

6 0

3 years ago

Simplify the expression: 2 – 6p - 4 + -3

Margaret [11]

Answer:

3 - 6p

Step-by-step explanation:

I think that's the answer :)

I hoped that helped!

7 0

2 years ago