$ABCD\ is\ parallelogram\ then\ :\\\\\underbrace{15x+2=9x+20}_{alternate\ angles}\ \ \ |subtract\ 2\ from\ both\ sides\\\\15x=9x+18\ \ \ \ |subtract\ 9x\ from\ both\ sides\\\\6x=18\ \ \ \ |divide\ both\ sides\ by\ 6\\\\\boxed{x=3}$

3 0

3 years ago

During a week in January in Cleveland, Ohio, the daily high temperatures were -4 °F, -2 °F, -12 °F, 5 °F, 12 °F, 16 °F, and 20 °

KIM [24]

Answer:

$\Delta T = T_{max,w} - T_{min,w}$

$\Delta T = 20\,^{\circ}F - (-12\,^{\circ}F)$

$\Delta T = 32\,^{\circ}F$

Step-by-step explanation:

The expression needed is the highest temperature of the week subtracted by the lowest temperature of the week. That is to say:

$\Delta T = T_{max,w} - T_{min,w}$

$\Delta T = 20\,^{\circ}F - (-12\,^{\circ}F)$

$\Delta T = 32\,^{\circ}F$

6 0

4 years ago