Answer:
C. SA = 148.8 ft
Step-by-step explanation:
3.1×8×6= 148.8
Here you go.................
Answer:
706.86ft²
Step-by-step explanation:
A=πr2=π·152≈706.85835ft²
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Answer:
4Joules
Step-by-step explanation:
According to Hooke's law which states that extension of an elastic material is directly proportional to the applied force provide that the elastic limit is not exceeded. Mathematically,
F = ke where
F is the applied force
K is the elastic constant
e is the extension
If a spring exerts a force of 6 N when stretched 3 m beyond its natural length, its elastic constant 'k'
can be gotten using k = f/e where
F = 6N, e = 3m
K = 6N/3m
K = 2N/m
Work done on an elastic string is calculated using 1/2ke².
If the spring is stretched 2 m beyond its natural length, the work done on the spring will be;
1/2× 2× (2)²
= 4Joules
Probability of rolling a number greater than 3:
P ( A ) = m/n
m =3, (numbers 4, 5, 6)
n = 6, (numbers 1 to 6).
P ( A ) = 3/6 = 1/2 = 0.5
