It is essential that you use the symbol " ^ " to denote exponention. See the following changes I have made.
9u^2v and which term or terms are like terms? 15u^2v. Why? because both have "u^2" in them.
She starts off with $10.25 and gets a raise of $0.50, so she earns $10.75 per hour. Then she gets a raise of 10%, so then 10.75 x 0.10 = 1.075, so she earns $11.825 per hour. Then her third raise is $0.50 so she earns $12.325 per hour. The raise for next summer is 5%, so 12.325 x 0.05 = 0.61625, so she earns $12.94125.
She will earn about $12.94 per hour starting off next summer.
Could you make the picture clear and back it up a little then i will see it better
Answer:
The answer to your question is:
Step-by-step explanation:
1.-






2sec
2.-
sec²x - tanxsecx






Answer:
the answer is b
Step-by-step explanation:
i did the quiz