Answer:
-63
Step-by-step explanation:
It’s doesn’t look like any of the anwsers are right..
The easiest way to solve this problem is by using the Pythagorean theorem :D
Pythagorean theorem: [-b +- sqrt(b^2 - 4ac)]/2a
5 = a
-1 = b
6 = c
therefore, by plugging these values in!
[-(-1) +- sqrt((-1)^2 - 4(5)(6))]/2(5)
[1 +- sqrt(1 - 120)]/10
Oh so we're using imaginary numbers, so in this case you'll need to know that i = sqrt(-1), so keep this in mind (I can see why this was so difficult)
[1 +- sqrt(119)*i]10
answers:
( 1 + i*sqrt(119) ) / 10
( 1 - i*sqrt(119) ) / 10
Answer:
-15
Step-by-step explanation:
-3 - 2(-6)
-3 -12
-15
Answer:

Step-by-step explanation:
We can write a rational function.
We need to make sure our denominator both have zeroes at 3 and 10.
Set an equation equal to zero to find the function




So we would represent that's as

and

Multiply the two binomial together.

Let our numbetator be any interger.
Use any equation as long as the quadratic is the denominator and the interger is the numerator.
