What is the average rate of change from x = −2 to x = 0?

Paige wants to sew lace around a round table cloth. The table cloth has a diameter of 6ft. About how much lace will Paige need?

Free_Kalibri [48]

It is B because u need enough for it to do it right

5 0

2 years ago

I have to find the value of x please help me will give brainliest to correct answer

Semenov [28]

Answer:

C. x = 5

Step-by-step explanation:

48 = 7x + 13

-13 -13

35 = 7x

5 = x

7 0

2 years ago

The National Center for Education Statistics surveyed a random sample of 4400 college graduates about the lengths of time requir

Paha777 [63]

Answer:

95% confidence interval for the mean time required to earn a bachelor’s degree by all college students is [5.10 years , 5.20 years].

Step-by-step explanation:

We are given that the National Center for Education Statistics surveyed a random sample of 4400 college graduates about the lengths of time required to earn their bachelor’s degrees. The mean was 5.15 years and the standard deviation was 1.68 years respectively.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean time = 5.15 years

$\sigma$ = sample standard deviation = 1.68 years

n = sample of college graduates = 4400

$\mu$ = population mean time

<em>Here for constructing 95% confidence interval we have used One-sample z test statistics although we are given sample standard deviation because the sample size is very large so at large sample values t distribution also follows normal.</em>

<u>So, 95% confidence interval for the population mean, </u> $\mu$ <u> is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5%

level of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

<u>95% confidence interval for</u> $\mu$ = [ $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $5.15-1.96 \times {\frac{1.68}{\sqrt{4400} } }$ , $5.15+1.96 \times {\frac{1.68}{\sqrt{4400} } }$ ]

= [5.10 , 5.20]

Therefore, 95% confidence interval for the mean time required to earn a bachelor’s degree by all college students is [5.10 years , 5.20 years].

8 0

3 years ago

I need help with no.7

ziro4ka [17]

Answer:

(a) 315°

(b) 3°

(c) 238°

Step-by-step explanation:

Bearings are measured clockwise from north. The triangle described is illustrated in the attachment.

The bearing of P from R is 180° different from the bearing of R from P it will be ...

135° +180° = 315° . . . . bearing of P from R

__

The bearing of Q from R is 48° more than the bearing of P from R, so is ...

315° +48° = 363°, or 3° . . . . bearing of Q from R

__

The angle QPR has a value that makes the sum of angles in the triangle equal to 180°. It is ...

180° -48° -55° = 77°

The bearing of Q from P is 77° less than the bearing of R from P, so is ...

135° -77° = 58°

As above, the reverse bearing from Q to P is ...

58° +180° = 238° . . . . bearing of P from Q

8 0

2 years ago

I need help with this problem <br> x²﹣9x﹣15=﹣5

icang [17]

Move all terms to the left side and set equal to zero. Then set each factor equal to zero.

x=10,−1

7 0

2 years ago

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