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Westkost [7]
3 years ago
10

Pentagon ABCDE is shown on the coordinate plane below:

Mathematics
2 answers:
goblinko [34]3 years ago
4 0
It's (5,2) , I took it already so here you go
nikitadnepr [17]3 years ago
3 0

Answer:  The correct option is (B) (5, 2).

Step-by-step explanation:  Given that the co-ordinates of the vertices of pentagon ABCDE are A(-2, 4), B(-6, 2), C(-5, -2), D(1, -2) and E(2, 2).

We are to find the co-ordinates of the point C', if the pentagon ABCDE is  rotated 180° around the origin to create pentagon A'B'C'D'E'.

We know that a rotation of 180° changes the co-ordinates of a point (x, y) according to the following rule:

(x, y)  ⇒  (-x, -y).

Therefore, the vertices of pentagon ABCD will transform to the vertices of pentagon A'B'C'D'E' as follows:

A(-2, 4)  ⇒ A'(2, -4),

B(-6, 2)   ⇒ B'(6, -2),

C(-5, -2)  ⇒  C'(5, 2),

D(1, -2)    ⇒  D'(-1, 2),

E(2, 2)    ⇒   E'(-2, -2).

Thus, the co-ordinates of the point C' are (5, 2).

Option (B) is correct.

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8 1/6

Step-by-step explanation:

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3 years ago
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What’s the answer?and how do you get it
Kay [80]

the solid is made up of 2 regular octagons, 8 sides, joined up by 8 rectangles, one on each side towards the other octagonal face.

from the figure, we can see that the apothem is 5 for the octagons, and since each side is 3 cm long, the perimeter of one octagon is 3*8 = 24.

the standing up sides are simply rectangles of 8x3.

if we can just get the area of all those ten figures, and sum them up, that'd be the area of the solid.

\bf \textit{area of a regular polygon}\\\\ A=\cfrac{1}{2}ap~~ \begin{cases} a=apothem\\ p=perimeter\\[-0.5em] \hrulefill\\ a=5\\ p=24 \end{cases}\implies A=\cfrac{1}{2}(5)(24)\implies \stackrel{\textit{just for one octagon}}{A=60} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{\textit{two octagon's area}}{2(60)}~~+~~\stackrel{\textit{eight rectangle's area}}{8(3\cdot 8)}\implies 120+192\implies 312

7 0
4 years ago
Solve the following proportion for u.<br> 5/8=u/9<br> Round the answer to the nearest tenth.
Firlakuza [10]

Answer:

5/10=u/9

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4 0
2 years ago
Write an equation of a ine in slope-intercept form that passes through a point (4,-6) and has a slope of -3.
Sindrei [870]

Answer:

y= -3x +6

Step-by-step explanation:

<u>slope-intercept form</u><u>:</u>

y=mx +c, where m is the slope and c is the y-intercept.

Given that the slope is -3, m= -3.

Susbt. m= -3 into the equation:

y= -3x +c

Since the line passes the point (4, -6),

(4, -6) lies on the line and must therefore satisfy the equation. Thus, susbt. (4, -6) into the equation to find the value of c.

y= -3x +c

when x=4, y= -6,

-6= -3(4) +c

-6= -12 +c

c= 12 -6

c= 6

Hence, the equation of the line is y= -3x +6.

7 0
3 years ago
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