A) x + y = 110
x - y = 40
B) Melvin swims for 35 minutes every day.
C) It is not possible
Step-by-step explanation:
Step 1:
Let x denote the duration for which Melvin plays tennis and y denote the duration for which he swims
Step 2 :
Part A :
Given that the total duration for which he plays and tennis is 110 minutes
so we have x + y = 110
Also given that he plays tennis for 40 minutes more than he swims
So, x = y+ 40 =>x-y = 40
So the linear pair of equations are
x + y = 110
x-y = 40
Step 3 :
Part B
Solving the above 2 equations we have
y+40+y = 110 = > 2y+ 40 = 110 = > y = 2y = 70 = >35
x = y+40 = 35+ 40 = 75
So Melvin plays tennis for 75 minutes and swims for 35 minutes every day.
Step 4 :
Part C
Given he plays and swims for 110 mins exactly, i.e x + y = 110
If Melvin plays tennis for 70 minutes , then x = 70, then the time for which he can swim is 110 - 70 = 40 mins.
He gets only 40 mins for swimming which is not 40 mins more than he plays tennis .
So this case is not possible.
Answer:
15
Step-by-step explanation:
The hypotenuse of a triangle is a² + b² = c².
12² + 9² = c²
144 + 81 = 225
√225 = 15
Answer:
Range remains the same.
Step-by-step explanation:
(1,3),(-2,1),(-5,-1) and (1,-2)
Answer:
a) 13 m/s
b) (15 + h) m/s
c) 15 m/s
Step-by-step explanation:
if the location is
y=x²+3*x
then the average velocity from 3 to 7 is
Δy/Δx=[y(7)-y(3)]/(7-3)=[7²+3*7- (3²+3*3)]/4= 13 m/s
then the average velocity from x=6 to to x=6+h
Δy/Δx=[y(6+h)-y(6)]/(6+h-6)=[(6+h)²+3*(6+h)- (6²+3*6)]/h= (2*6*h+3*h+h²)/h=2*6+3= (15 + h) m/s
the instantaneous velocity can be found taking the limit of Δy/Δx when h→0. Then
when h→0 , limit Δy/Δx= (15 + h) m/s = 15 m/s
then v= 15 m/s
also can be found taking the derivative of y in x=6
v=dy/dx=2*x+3
for x=6
v=dy/dx=2*6+3 = 12+3=15 m/s
Answer:
(4, -8)
Step-by-step explanation:
The components of a vector are found by subtracting the tail from the head.
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Head - Tail = (1, -6) -(-3, 2) = (1 -(-3), -6 -2) = (4, -8)
⇒ The component form is (4, -8), or maybe 4<em>i</em> -8<em>j</em>.
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<em>Additional comment</em>
There are many ways that the components of vectors can be described. The particular format you are expected to use will likely be found in your curriculum materials.
