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See the picture attached to better understand the problem
we know that
If two secant segments are drawn to a <span>circle </span><span>from an exterior point, then the product of the measures of one secant segment and its external secant segment is equal to the product of the measures of the other secant segment and its external secant segment.
</span>so
jl*jk=jn*jm------> jn=jl*jk/jm
we have
<span>jk=8,lk=4 and jm=6
</span>jl=8+4----> 12
jn=jl*jk/jm-----> jn=12*8/6----> jn=16
the answer is
jn=16
we know that
If two secant segments are drawn to a <span>circle </span><span>from an exterior point, then the product of the measures of one secant segment and its external secant segment is equal to the product of the measures of the other secant segment and its external secant segment.
</span>so
jl*jk=jn*jm------> jn=jl*jk/jm
we have
<span>jk=8,lk=4 and jm=6
</span>jl=8+4----> 12
jn=jl*jk/jm-----> jn=12*8/6----> jn=16
the answer is
jn=16
Answer:
Swimming one time around the pool is 56.5 ft
Step-by-step explanation:
Swimming 18 ft from one side of her circular pool to the other, swimming straight through the center means the circular swimming pool has a diameter of d=18 ft.
The circumference of the circle is calculated using:
where d=18 is the diameter and π=3.14 as given.
We substitute the values to get:
We approximate to the nearest tenth to get: