Break down the problem into these two equations;
x = -31
-x = -31
Solve for the 1st equation; x = -31
x = -31
Solve for the 2nd equation; -x = -31
x = 31
Collect all solutions
x = ±31
Check the solution
When x = -31, the original equation; |x| = -31 does not hold true. Thus, we will drop x = -31 from the solution set.
Check the solution again;
When x = 31, the original equation |x| = -31 does not hold true as well. Thus we will drop x = 31 from the solution set.
Therefore,
<u>No solution exists to this equation. </u>
Answer:
Y=s^2/36 and y=5.7;14.3 ft
Step-by-step explanation:
The question was not typed correctly. Here, a better version:
<em>The aspect ratio is used when calculating the aerodynamic efficiency of the wing of a plane for a standard wing area, the function A(s)=s^2/36 can be used to find the aspect ratio depending on the wingspan in feet. If one glider has an aspect ratio of 5.7, which system of equations and solution can be used to represent the wingspan of the glider? Round solution to the nearest tenth if necessary. </em>
<em>
</em>
<em>Y=s^2/36 and y=5.7;14.3 ft
</em>
<em>Y=5.7s^2 and y=36; s=2.5ft
</em>
<em>Y=36s^2 and y=0; s=0.4 ft
</em>
<em>Y=s^2/36 +5.7 and y=0; s=5.5 ft</em>
In the function A(s)=s^2/36 A(s) represents the aspect ratio and s the wingspan. If one glider has an aspect ratio of 5.7, then A(s) = 5.7. We want to know the wingspan of the glider. Replacing A(s) by Y we get the following system of equation:
Y=s^2/36
with y = 5.7
5.7 = s^2/36
5.7*36 = s^2
√205.2 = s
14.3 ft
Answer:
b.
Step-by-step explanation:
The quantity x minus 2y is (x - 2y), then we add 3.
Find the GCF (Greatest Common Factor)
GCF = 2x
Factor out the GCF (Write the GCF first and then, in parentheses, divide each term by the GCF.)
2x (2x^3/2x + 4x^2/2x + 6x/2x)
Simplify each term in parentheses
-2x(x^2 + 2x + 3)
<u>Answer D. -2(x^2 + 2x + 3)</u>
Answer:
2 students in each group
Step-by-step explanation:
If there were 5 groups and after a while 7 students leave early and 3 students remain to do the activity, if you add 7 + 3 = 10 divide it by 5, the number of groups in the activity, you would get 2 students in each group.
