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3 years ago

5

There are 70 fish in the tank. Half of the fish have orange spots and 1/5 of the remaining fish have orange and black spots. How

many fish have orange and black spots?

1 answer:

Feliz [49]3 years ago

8 0

Answer:

7 orange and black fish

Step-by-step explanation:

a fifth of the remaining fish is 7 because you are doing 35*1/5. 35 is the remaining number of fish because already half of the other fish is 35 and they are orange

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Can someone help plssss<br> which of the equations below could be the equation of this parabola?

RideAnS [48]

Answer:

C

Step-by-step explanation:

Both of the y= make upward parabolas

It is also going into the positive direction so it is $x = \frac{1}{4}y^2$

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2 years ago

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Find (3) if<br> f(x)=x2 + 2x2-x-1

Olenka [21]

Answer:

The correct answer is:

$f(3)=23$

Step-by-step explanation:

By evaluating first, and then the mathematical calculation, we have:

$f(3)= 3^{2} + 2 ×3^{2} - 3 -1$

$= 9 +18 -3-1$

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2 years ago

Which is bigger 100 kg or 1,000 grams<br><br><br> Please answer is for todayyyyy

charle [14.2K]

100 kg becouse 1000 grams is egual 1 kg

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2 years ago

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The ordered pairs (0,-5) (-1,-7) and (1,n) are solutions of the same linear equation. find n

Arada [10]

The three points are on the same line, so the slopes formed by any of the two points stay the same
[-7-(-5)]/(-1-0)=[n-(-5)/(1-0)
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5 0

2 years ago

The sum of the diagonals of a rhombus is 5√2.

Alex

Greetings!
Let ABCD be a rhombus
AC + BD = 5√2 cm

Area of ABCD = Ar△ABD + Ar △BCD
$= \frac{1}{2} \times BD \times AO + \frac{1}{2} \times BD \times OC$
$= \frac{1}{2} BD (AO + OC)$
$\frac{1}{2} BD \times AC$

$So, \frac{ BD \times AC}{2} = 4 \: cm {}^{2}$
$BD \times AC = 8$
$Now, AC + \: BD = 5 \sqrt{2}$

Squaring both sides, we get
$AC {}^{2} + BD {}^{2} + 2 AC.BD =50$
$AC {}^{2} + BD {}^{2} + 2 \times 8 = 50$
$AC {}^{2} + BD {}^{2} = 50 - 16$
$AC {}^{2} + BD {}^{2} = 34$

In △AOB, we have
$OA {}^{2} + OB {}^{2} =AB {}^{2}$
$( \frac{ AC }{2} ) {}^{2} + ( \frac{ BD}{2} ) {}^{2} = AB {}^{2}$
$\frac{ AC {}^{2} } {4} + \frac{ BD {}^{2} }{4} = AB {}^{2}$
$AC {}^{2} + BD {}^{2} = 4 AB {}^{2}$
$34 = 4 AB {}^{2}$

Square rooting both sides
$\sqrt{34} = 2 AB$
$Perimeter = 4 \: AB \\ = 2 \times 2 \: AB \\ = 2 \: \times \sqrt{34 } \\ = 2 \sqrt{34 \: } units$ .

Hope it helps!

7 0

3 years ago