Answer:
The probability that a part is good given that it passed the inspection machine is P=0.978.
Step-by-step explanation:
As the inspection machine detect and discard any part that is completely defective, only the good and partially defective parts passed this inspection.
Then, if we have:
Probability of being a good part P(G)=0.90
Probability of being a patially defective part P(P)=0.02
Probability of being a completely defective part P(D)=0.08.
Probability of passing the inspection machine = 1-P(D)=1-0.08=0.92
Then, the probability of having a good part, given that it passed the inspection machine is:

The IQR is the difference between Quartile 1 and Quartile 3
Q 1 = 17 and Q 3 = 30
Q3 - Q1 = 30 - 17 = 13
C. Euclid is known as the father of Geometry
Answer:
the answer is c!
Step-by-step explanation:
Answer:
64%
Step-by-step explanationI added total and points earned and divided 66/102 and I got 0.64. I moved my decimal 2 places to the right and got 64%