Step-by-step explanation:
Hey there!
Given sequences are; 2 , 13 , 24 , 35 , _ , _ .
Now,
Common difference (d) = 2nd term - 1st term. = 13-2 = 11
When we subtract 1st term from 2nd term we find 11 and when we subtract 2nd term from 3rd term we get 11. This means our common difference is 11.
Now, let's find the nrh term of the sequence.
nth term= a1 + (n-1)d ( <em>a1= 1st term, d= common</em> <em>difference</em>)
nth = 2+ (n-1) 11
= 2 + 11n - 11
= 11n - 9
Let's check if we have got nth term correct.
a1= 1*11 - 9 = 2
a2 = 2*11-9 = 13
a3 = 3*11 - 9 = 24
a4 = 4*11-9 = 35
So, we got our nth term.
Let's find remaining sequence.
a5= 5*11 - 9 = 46.
a6= 6*11 - 9 = 57.
Therefore, the remaining terms are : 46 and 57.
<em><u>Hope</u></em><em><u> it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Answer:
n ≥ -17
Step-by-step explanation:
Writing a symbolic inequality, we get:
10 - 3n ≤ 61
Solve this for 3n by adding 3n to both sides of this equation:
10 ≤ 61 + 3n
Solve for n by subtracting 61 from both sides and then dividing all of the resulting terms by 3:
-51 ≤ 3n (divide both sides by 3):
-17 ≤ n, or
n ≥ -17
One way you could solve this is to just multiply the top and bottom out so that you get 9/81, reducing it by 9/9 to get 1/9 or option C.
Another way would be to do
since dividing numbers with exponents would be subtracting the bottom exponent from the top exponent, provided that the base number (in this case 3) is the same for both. For this method, you would get
, which is equal to 1/9 or .1 repeating, the same answer that you'd get with the first method.
(a) without replacement:
P(S)=13/52=1/4
P(SS)=(1/4)*(12/51)=1/17
Probability of selecting two spades without replacement is 1/17.
(b) with replacement
P(S)=13/52=1/4
P(SS)=(1/4)(13/52)=1/16
Probability of selecting two spades with replacement is 1/16.
