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3 years ago

6

I just need #21 and #23 answered please.

2 answers:

kykrilka [37]3 years ago

7 0

#21: Even
#23: Neither

egoroff_w [7]3 years ago

5 0

Answer:

<h2><em><u>2</u></em><em><u>1</u></em><em><u>.</u></em><em><u> </u></em><em><u>y</u></em><em><u>=</u></em><em><u>x⁴</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>even</u></em><em><u> </u></em><em><u>because</u></em><em><u> </u></em><em><u>y×</u></em><em><u>x⁴</u></em><em><u>=</u></em><em><u>4</u></em><em><u>x</u></em><em><u>y</u></em><em><u> </u></em><em><u>4</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>even</u></em><em><u> </u></em><em><u>number</u></em><em><u> </u></em><em><u>so</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>even</u></em><em><u> </u></em><em><u>number</u></em><em><u> </u></em></h2><h2><em><u>2</u></em><em><u>3</u></em><em><u>.</u></em><em><u> </u></em><em><u>y</u></em><em><u>=</u></em><em><u>x</u></em><em><u>+</u></em><em><u>2</u></em><em><u>=</u></em><em><u>neither</u></em><em><u> </u></em><em><u>because</u></em><em><u> </u></em><em><u>y×x</u></em><em><u>+</u></em><em><u>2</u></em><em><u>=</u></em><em><u>2</u></em><em><u>x</u></em><em><u>y</u></em><em><u> </u></em><em><u>2</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>even</u></em><em><u> </u></em><em><u>number</u></em><em><u> </u></em><em><u>but</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>question</u></em><em><u> </u></em><em><u>there</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>+</u></em><em><u> </u></em><em><u>.</u></em><em><u>=</u></em><em><u>×</u></em><em><u>+</u></em><em><u>=</u></em><em><u>+</u></em><em><u> </u></em><em><u>so</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>neither</u></em><em><u> </u></em></h2>

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