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tia_tia [17]
3 years ago
6

I just need #21 and #23 answered please.

Mathematics
2 answers:
kykrilka [37]3 years ago
7 0
#21: Even
#23: Neither
egoroff_w [7]3 years ago
5 0

Answer:

<h2><em><u>2</u></em><em><u>1</u></em><em><u>.</u></em><em><u> </u></em><em><u>y</u></em><em><u>=</u></em><em><u>x⁴</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>even</u></em><em><u> </u></em><em><u>because</u></em><em><u> </u></em><em><u>y×</u></em><em><u>x⁴</u></em><em><u>=</u></em><em><u>4</u></em><em><u>x</u></em><em><u>y</u></em><em><u> </u></em><em><u>4</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>even</u></em><em><u> </u></em><em><u>number</u></em><em><u> </u></em><em><u>so</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>even</u></em><em><u> </u></em><em><u>number</u></em><em><u> </u></em></h2><h2><em><u>2</u></em><em><u>3</u></em><em><u>.</u></em><em><u> </u></em><em><u>y</u></em><em><u>=</u></em><em><u>x</u></em><em><u>+</u></em><em><u>2</u></em><em><u>=</u></em><em><u>neither</u></em><em><u> </u></em><em><u>because</u></em><em><u> </u></em><em><u>y×x</u></em><em><u>+</u></em><em><u>2</u></em><em><u>=</u></em><em><u>2</u></em><em><u>x</u></em><em><u>y</u></em><em><u> </u></em><em><u>2</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>even</u></em><em><u> </u></em><em><u>number</u></em><em><u> </u></em><em><u>but</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>question</u></em><em><u> </u></em><em><u>there</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>+</u></em><em><u> </u></em><em><u>.</u></em><em><u>=</u></em><em><u>×</u></em><em><u>+</u></em><em><u>=</u></em><em><u>+</u></em><em><u> </u></em><em><u>so</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>neither</u></em><em><u> </u></em></h2>

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a. The exact value of cosθ = -5/√74

b. The exact value of secθ = -√74/5

c. The exact value of cotθ = 5/7

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So, r = √(x² + y²) where

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Since the trigonometric ratio cosθ = x/r

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So, the exact value of cosθ = -5/√74

<h3>The value of the trigonometric ratio secθ</h3>

Since the trigonometric ratio, secθ = r/x

Substituting the values of x and r into the equation, we have

secθ = r/x

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<h3>The value of the trigonometric ratio cotθ</h3>

Since the trigonometric ratio cotθ = x/y

Substituting the values of x and y into the equation, we have

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cotθ = -5/-7

cotθ = 5/7

So,  the exact value of cotθ = 5/7

Learn more about trigonometric ratios here:

brainly.com/question/1518222

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2 years ago
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a

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