Answer:
16 hope dat helps
Step-by-step explanation:
Answer: 6(x²-4x+4-4)+1=0, 6(x-2)²-24+1=0, 6(x-2)²=23, x-2=±√(23/6), x=2±√(23/6)=2±1.95789, so x=3.95789 or 0.04211 approx. these are the zeros.
step by step explanation:
\boxed{\boxed{\dfrac{12+\sqrt{138}}{6},\ \dfrac{12-\sqrt{138}}{6}}}
Solution-
The quadratic function is,
6x^2-24x + 1
a = 6, b = -24, c = 1
x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}
=\dfrac{-(-24)\pm \sqrt{-24^2-4\cdot 6\cdot 1}}{2\cdot 6}
=\dfrac{24\pm \sqrt{576-24}}{12}
=\dfrac{24\pm \sqrt{552}}{12}
=\dfrac{24\pm 2\sqrt{138}}{12}
=\dfrac{12\pm \sqrt{138}}{6}
=\dfrac{12+\sqrt{138}}{6},\ \dfrac{12-\sqrt{138}}{6}
Answer:
7y-15+2y= 9y-15
9y-15
.....
Step-by-step explanation:
Hot dogs- 4 packs (9 times 4 = 36)
Buns - 3 packs (12 times 3 = 36)
The inverse functions of sine, cos and tan functions are csc, sec and cot respectively.
<u>Step-by-step explanation:</u>
The reciprocals of sine, cos and tan functions are csc, sec and cot functions. The reciprocal of cosine function is secant, (sec) sec θ = 
The inverse or reciprocal function is cosecant (csc), 
The inverse tangent function is cotangent (cot) , expressed in two ways: 
or 
So 
then its reciprocal or inverse is termed as cot θ.
