Answer:
Step-by-step explanation:
a) It can be convenient to use the square root function as one being defined only for values greater than or equal to some number. Here, we need to shift that function 3 units to the left, so its domain is [-3, ∞).
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b) One way to put holes in a function is to put vertical asymptotes there. This function can be defined to have vertical asymptotes at x=2 and x=4 so those values are excluded from the domain.
Complete question is;
Find the exact values of the six trigonometric functions 0 if the terminal side of 0 in standard position contains the points(-5,-4).
Answer:
Sin θ = -4/√41
Cos θ = -5/√41
tan θ = 4/5
Cosec θ = (√41)/-4
Sec θ = (√41)/-5
Cot θ = 5/4
Step-by-step explanation:
Now, we are given the point (-5, -4)
These are x and y points.
They will form a triangle and we know that from pythagoras theorem;
x² + y² = r²
Where r is the distance between the point and the origin
Thus;
r² = (-5)² + (-4)²
r² = 25 + 16
r = √41
So, y is the opposite side of the triangle while x is the adjacent side with r being the hypotenuse.
Thus, the trigonometric ratios are;
Sin θ = opp/hyp = -4/√41
Cos θ = adj/hyp = -5/√41
tan θ = opp/adj = -4/-5 = 4/5
Cosec θ = 1/Sin θ = 1/(-4/√41) = (√41)/-4
Sec θ = 1/cos θ = 1/(-5/√41) = (√41)/-5
Cot θ = 1/tan θ = 1/(4/5) = 5/4
1.88m= 188 cm. 188cm+6cm=194cm
♡ The Question ♡
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3.602 × 10 − 4
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♡ The Answer ♡
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32.02
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♡ The Explanation/Step-By-Step ♡
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3.602 x 10 - 4
Multiply the numbers: 3.602 x 10 = 36.02
= 36.02 - 4
Subtract the numbers: 36.02 - 4 = 32.02!
= 32.02
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♡ Tips ♡
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