Answer:
Step-by-step explanation:
m = 4
![y -y_{1}=m(x -x_{1})\\\\y - 4 = 4(x -[-1])\\\\y - 4 = 4(x + 1)\\\\y -5= 4x + 4\\\\y = 4x + 4 + 5\\y = 4x + 9](https://tex.z-dn.net/?f=y%20-y_%7B1%7D%3Dm%28x%20-x_%7B1%7D%29%5C%5C%5C%5Cy%20-%204%20%3D%204%28x%20-%5B-1%5D%29%5C%5C%5C%5Cy%20-%204%20%3D%204%28x%20%2B%201%29%5C%5C%5C%5Cy%20-5%3D%204x%20%2B%204%5C%5C%5C%5Cy%20%3D%204x%20%2B%204%20%2B%205%5C%5Cy%20%3D%204x%20%2B%209)
Answer:
First one
Step-by-step explanation:
y = -3x + 5
Make x the subject
3x = 5 - y
x = (5 - y)/3
Interswitch variables
(f^-1)(x) = (5 - x)/3
= 5/3 - x/3
Answer:
soln
let x=n in order to differentiate btn x and multiplication sign.
first of all we apply cross multiplication.
14/4×n/2
(4×n)=(14×2)
open blacket
4n=28
we divide by 4 both side
n=7
therefore
x=7
Answer:
A) x² + 2x + 6
B) x² + 2x - 7
C) ¼(x²+2x+1))
D) 6x²+12x+6
E) -x²-2x-1
Step-by-step explanation:
A) f(x) + 5 =x²+2x+1 + 5
= x² + 2x + 6
B) f(x)-8,=x^2+2x+1-8
= x² + 2x - 7
C) ¼f(x) = ¼(x²+2x+1)
D) 6f(x) = 6(x²+2x+1) = 6x²+12x+6
E) -f(x) = -(x²+2x+1) = -x²-2x-1
Answer:
23
Step-by-step explanation:
