All categories

2 years ago

HELPPPP ASAP it’s so confusing I’ll brainlist whoever gets it.

Mathematics

1 answer:

den301095 [7]2 years ago

4 0

Answer:

probability she does not win badminton: 1/10

probability she does not win tennis: 3/5

not sure what the other tree is supposed to be

i think the probability of her winning both is 11/15

Step-by-step explanation:

i havent done this in a while so i could be wrong:/ sorry if it is

You might be interested in

Find the value of y.

mixas84 [53]

Answer:

y=9

Step-by-step explanation:

3 0

3 years ago

I NEED HELP ASAP!! did i do correct??

Aleks [24]

Answer:

If I were to be honest I think you did it perfectly

5 0

3 years ago

Becky, an artist, plans to paint and sell some miniature paintings. She just bought some brushes for $1, and paint and canvas fo

Veronika [31]

Answer:

After one unit is sold, Becky will break-even.

Step-by-step explanation:

Giving the following information:

Fixed costs= $1

Unitary variable cost= $21

Selling price= $22

<u>The break-even point is the number of units required to cover the fixed costs after deducting from the selling price the variable components. At this point, net income is zero</u>.

Break-even point in units= fixed costs/ contribution margin per unit

Break-even point in units= 1 / (22 - 21)

Break-even point in units= 1

After one unit is sold, Becky will break-even.

8 0

2 years ago

852÷6how to explain your answer

docker41 [41]

142 is the answer
$852 \div 6 =$

7 0

3 years ago

Read 2 more answers

You decide to put $5000 in a savings account to save $6000 down payment on a new car. If the account has an interest rate of 7%

bezimeni [28]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill&\$6000\\ P=\textit{original amount deposited}\dotfill &\$5000\\ r=rate\to 7\%\to \frac{7}{100}\dotfill &0.07\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years \end{cases}$

$\bf 6000=5000\left(1+\frac{0.07}{12}\right)^{12\cdot t}\implies \cfrac{6000}{5000}\approx (1.0058)^{12t}\implies \cfrac{6}{5}\approx(1.0058)^{12t} \\\\\\ \log\left( \cfrac{6}{5} \right)\approx \log[(1.0058)^{12t}]\implies \log\left( \cfrac{6}{5} \right)\approx 12t\log(1.0058) \\\\\\ \cfrac{\log\left( \frac{6}{5} \right)}{12\log(1.0058)}\approx t\implies 2.63\approx t\impliedby \textit{about 2 years, 7 months and 16 days}$

6 0

3 years ago