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Ivanshal [37]
3 years ago
6

Compute |1-3+5-7+...+13-15|

Mathematics
1 answer:
Allushta [10]3 years ago
4 0

Answer:

8

Step-by-step explanation:

There are a couple different ways you can solve this, but this is generally the quickest way.

Identify a pattern in the problem. We can see that 1-3=-2,  5-7=-2, and so on. Subtracting every two odd numbers (without repeating any numbers) in that problem will always give us the same answer: -2.

So, we see how many pairs of odd numbers there are.

1 and 3,  5 and 7,  9 and 11,  13 and 15. We have <u>four</u> pairs of odd numbers. We can just multiply -2 by 4, which leaves us with an answer of -8.

Finally, since this is also an absolute value equation, the answer will be positive, so the final answer is 8.

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Help Homework.
Ksju [112]

Answer:

1/24

Step-by-step explanation:

5/12 - 3/8=?

The first step is to find a denominator (bottom number) that is the same for both fractions. In this case, 24 works.

10/24 - 9/24 = ?

1/24

8 0
3 years ago
Read 2 more answers
What is a simple way to solve for the sum and difference of 2 cubes? For example, 27+64<img src="https://tex.z-dn.net/?f=x%5E3"
salantis [7]

Answer:

(3 + 4x)(9 - 12x + 16x²) = 0

(4m - 1)(16m² + 4m + 1) = 0

Step-by-step explanation:

Here we have to solve the sum of two cubes which is 27 + 64x^{3}

Now, the equation is 27 + 64x^{3} = 0

⇒ 3³ + (4x)³ = 0

⇒ (3 + 4x)[3² - 3(4x) + (4x)²] = 0

⇒ (3 + 4x)(9 - 12x + 16x²) = 0

So, (3 + 4x) = 0 or (9 - 12x + 16x²) = 0

Therefore, from the above two relation we can solve for x.

One root will be - \frac{3}{4} and the others we will get by applying Sridhar Acharya Formula, which will give a pair of conjugate imaginary roots of the equation.  

Again, we have to solve the difference of two cubes which is 64m^{3} - 1

Now, the equation is 64m^{3} - 1 = 0

⇒ (4m)³ - 1³ = 0

⇒ (4m - 1)[(4m)² + 4m(1) + 1²] = 0

⇒ (4m - 1)(16m² + 4m + 1) = 0

So, (4m - 1) = 0 or (16m² + 4m + 1) = 0

Therefore, from the above two relation we can solve for m.

One root will be \frac{1}{4} and the others we will get by applying Sridhar Acharya Formula, which will give a pair of conjugate imaginary roots of the equation.  (Answer)

8 0
3 years ago
PLEASE HELP! 50 POINTS! (Solve each system of equations. Determine which quadrant the solution lies in.)
Sloan [31]

Answer:

wet

Step-by-step explanation:

3 0
3 years ago
PLEASE HELPPPPP
natulia [17]
Take Saturdays total of $620 and subtract Fridays total of $460 to get $160. Divide that by the difference of the number of pies sold on Friday and Saturday to get $8. Take the $8 and multiply by number of pies sold on Friday (20) to get $160. Take that number and subtract it from the total sold on Friday ($460) to get $300. Divide that by how many cakes were sold on Friday (30) and get $10.
So therefore:

Pies - $8 each
Cakes - $10 each
6 0
4 years ago
round 205,721 to the nearest hundred thousands , to the nearest ten thousands and to the nearest thousands
Dovator [93]
To the nearest hundred thousandths: 200,000
To the nearest ten-thousandths: 210,000
To the nearest thousands: 206,000
7 0
3 years ago
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