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2 years ago

12

kyle drew tree line segments with these lenngths: 2/4" , 2/3" , 2/6" list the fractions in order from least to graiter

1 answer:

exis [7]2 years ago

6 0

First you find a common denominator, which is 12 ( as 4,3 and 6 all go into 12). So 2/4 becomes 6/12, as 4 multiplied by 3 is 12 and whatever you do to the denominator you must do to the numerator. Then 2/3 becomes 8/12. And 2/6 becomes 4/12. If you put these in order the answer is:

2/6, 2/4, 2/3

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Given P space equals space P subscript 0 space plus space rho g h, your objective is to determine the uncertainty of P by measur

son4ous [18]

Answer:

the g's contributing term for the overall uncertainty of P is $dP_g = [\frac{dg}{g}]$

Step-by-step explanation:

From the question we are told that

The pressure is $P = P_o + \rho gh$

The first step in determining the uncertainty of P in by obtaining the terms in the equation contributing to it uncertainty and to do that we take the Ln of both sides of the equation

$ln P = lnP_o + ln(\rho gh )$

=> $ln P = lnP_o + ln \rho + ln g + ln h$

Then the next step is to differentiate both sides of the equation

$\frac{d(ln P)}{dP} = \frac{d(ln P_o)}{dP_o} + \frac{d(ln \rho)}{d\rho} +\frac{d(ln g)}{dg} + \frac{d(ln h)}{dh}$

=> $\frac{dP}{P} = \frac{dP_o}{P_o} + \frac{d \rho}{\rho} +\frac{d g}{g} + \frac{d h}{h}$

We asked to obtain the contribution of the term g to the uncertainty of P

This can deduced from the above equation as

$dP_g = [\frac{dg}{g}] P$

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3 years ago

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Step-by-step explanation:

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