Answer:
B. 20.41
Step-by-step explanation:
I hope this helps! pls brainliest:D
The area of a rectangle is A=LW, the area of a square is A=S^2.
W=S-2 and L=2S-3
And we are told that the areas of each figure are the same.
S^2=LW, using L and W found above we have:
S^2=(2S-3)(S-2) perform indicated multiplication on right side
S^2=2S^2-4S-3S+6 combine like terms on right side
S^2=2S^2-7S+6 subtract S^2 from both sides
S^2-7S+6=0 factor:
S^2-S-6S+6=0
S(S-1)-6(S-1)=0
(S-6)(S-1)=0, since W=S-2, and W>0, S>2 so:
S=6 is the only valid value for S. Now we can find the dimensions of the rectangle...
W=S-2 and L=2S-3 given that S=6 in
W=4 in and L=9 in
So the width of the rectangle is 4 inches and the length of the rectangle is 9 inches.
Answer:
x=-2
Step-by-step explanation:
Since it's a vertical line the answer is going to be x= which ever number the line is on. In this case x=-2
9514 1404 393
Answer:
42 cm²
Step-by-step explanation:
The attachment shows a couple of ways the figure can be considered.
a) Left and Right rectangles that are 5 cm high and 3 cm wide, together with a central rectangle that is 3 cm high and 4 cm wide. Then the total area is ...
5×3 + 3×4 + 5×3 = 15 + 12 + 15 = 42 . . . . cm²
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b) An enclosing rectangle that is 5 cm high and 10 cm wide with a cut-out that is 2 cm high and 4 cm wide. Then the total area is ...
5×10 -2×4 = 50 -8 = 42 . . . . cm²
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The area of the irregular figure is 42 cm².