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2 years ago

Find a degree 3 polynomial having zeros -5, 1 and 5 and the coefficient of x^3 equal 1

Mathematics

1 answer:

mote1985 [20]2 years ago

7 0

Answer:

$x^3 -x^2 -25x +25$

Step-by-step explanation:

$\text{The roots are,}~ \alpha = -5,~ \beta = 1 ~ \text{and}~ \gamma = 5\\\\\text{The polynomial is,}\\\\~~~x^3 - (\alpha + \beta + \gamma)x^2+(\alpha \beta + \beta \gamma+ \gamma \alpha)x - \alpha\beta \gamma\\\\=x^3 - (-5+1+5)x^2 +(-5 \cdot 1 + 1 \cdot 5 + 5 \cdot -5)x - (-5)(1)(5)\\\\=x^3 -(0+1)x^2 + (-5+5-25)x +25\\\\=x^3 -x^2 -25x +25$

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Granny Smith was able to make 61.75 ounces of strawberry jelly

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3 years ago

What is the angle of DBC

Licemer1 [7]

When added, these two angles are supplementary, meaning that their sum is 180. This means that we can do the following to find x, and eventually DBC:

3x+67+4x+50=180
Simplifies to:
7x+117=180
Then by the Subtraction Prop. of Equality:
7x=63
Then divide by 7 on both sides to get that x=9.

We then substitute 9 into angle DBC.
4(9)+50
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8 0

3 years ago

Solve (x+y) if x=-1/2 and y=-3

bixtya [17]

Answer:

$-3\frac{1}{2}$

Step-by-step explanation:

Solve

$(x+y)$

For x=-1/2 and y=-3

substitute the value of x and the value of y in the expression above

$x+y=(-\frac{1}{2})+(-3)$

Remember that

$(+1)(-1)=-1$

$x+y=-\frac{1}{2}-3=\frac{-1-6}{2}=-\frac{7}{2}$

Convert to mixed number

$-\frac{7}{2}=-\frac{6}{2}-\frac{1}{2}=-3\frac{1}{2}$

7 0

3 years ago

Jina wanted to study how the area of a rectangle changes with the length if it’s width is fixed. She computed the areas of sever

olganol [36]

Answer:

The domain and the range of the function are, respectively:

$Dom\{f\} = [0\,m,5\,m]$

$Ran\{f\} = [0\,m^{2}, 10\,m^{2}]$

Step-by-step explanation:

Jina represented a function by a graphic approach, where the length, measured in meters, is the domain of the function, whereas the area, measured in square meters, is its range.

$Dom\{f\} = [0\,m,5\,m]$

$Ran\{f\} = [0\,m^{2}, 10\,m^{2}]$

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3 years ago

Find the area and perimeter

spin [16.1K]

Answer:

area (A) =(9x+108)unit^2

perimeter (P) =(2x+42) units

Step-by-step explanation:

area(A) =length(l) × breadth(b)

perimeter(P) =2(l+ b) {which is sum of all sides}

so, l = 7+x+5 = (x+12) units and b = 9 units

now, A=(x+12) × 9 units^2

=(9×x + 12×9 ) units^2

Therefore,

A =(9x+108)unit^2

next, P=2{(x+12)+9}

=2(x+21)

Hence,

P=(2x+42) units

3 0

3 years ago