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poizon [28]
2 years ago
9

Find a degree 3 polynomial having zeros -5, 1 and 5 and the coefficient of x^3 equal 1

Mathematics
1 answer:
mote1985 [20]2 years ago
7 0

Answer:

x^3 -x^2 -25x +25

Step-by-step explanation:

\text{The roots are,}~ \alpha  = -5,~ \beta = 1 ~ \text{and}~ \gamma = 5\\\\\text{The polynomial is,}\\\\~~~x^3 - (\alpha + \beta + \gamma)x^2+(\alpha \beta + \beta \gamma+ \gamma \alpha)x - \alpha\beta \gamma\\\\=x^3 - (-5+1+5)x^2 +(-5 \cdot 1 + 1 \cdot 5 + 5 \cdot -5)x - (-5)(1)(5)\\\\=x^3 -(0+1)x^2 + (-5+5-25)x +25\\\\=x^3 -x^2 -25x +25

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Answer:

La arista de la bodega debe medir 6 metros.

Step-by-step explanation:

Podemos encontrar la arista de la bodega sabiendo su volumen:

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En donde:

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La arista del cubo es:

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Espero que te sea de utilidad!

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3 years ago
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Hope this helps :)

Have a nice day!

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