Answer:– 1 – cos(ϴ)
Step-by-step explanation:
I forgot what they’re called but the angles opposite to each other are the same degree. It’s a theorem, just search up the name
Answer:
12 pull
As 48 seconds + 20 seconds push = 68 seconds
Step-by-step explanation:
Because she did 10 push = 20 seconds = 2 seconds each
12 pull = 48 seconds = 4 seconds each
= 68 seconds combined.
Workings;
18 seconds found for the first set
We then find a divider of 68 and know that
6 x 3 = 18 seconds push
12 x 3 =36 seconds pull T= 54
14 left over = 1 x 12 seconds pull
+ 2 seconds push
= 10 push = 20 seconds combined.
= 12 pull = 48 seconds combined.
Answer:
45+67×56=37,565
Step-by-step explanation:
i hope it helps you
Answer:

Step-by-step explanation:
Given




Required
The perimeter
To do this, we first calculate the side lengths using distance formula

So, we have:








The perimeter is:


