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Brrunno [24]
3 years ago
9

I will give brainliest

Mathematics
2 answers:
ollegr [7]3 years ago
7 0

the correct answer would be D 851.50

Fynjy0 [20]3 years ago
4 0
The option A and B would be wrong since it was less than the minimum value of the function. To find the cost, you just need to replace the x variable with time after 2005.
If the time is 2025 it will be
x= 2025-2005= 20

y = 15.7x + 459
y = 15.7(20) + 459
y = 314+ 459 = <span>$773.00
</span>
If the time is 2030 it will be
x= 2030-2005= 25

<span>y = 15.7x + 459
</span><span>y = 15.7(25) + 459
</span>y = 392.5+ 459 =<span>$851.50</span><span>
</span>
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What is 10 x 10 to the power 8
barxatty [35]

Your answer is

1,000,000,000 (one billion)

Hope this helps.

5 0
2 years ago
F(x) = 3x, g(x) = 1/3f(x). Find g(0)
schepotkina [342]

Answer:

f(1/3)=3 try that its probably right

4 0
3 years ago
If an object falls 40 meters in 4 seconds,how far will it fall in6 seconds​
sweet [91]

Answer:

60 seconds

Step-by-step explanation:

step 1.) find how many meters it falls per second

          40m / 4sec = 10m/s

step 2.) use the equation above to find in terms of the question

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4 0
3 years ago
Help me Please....................
MakcuM [25]

9514 1404 393

Answer:

  1.3363

Step-by-step explanation:

The basic idea here is to find an expression for the direction vector between a point on L1 and a point on L2. Then, solve for the points on L1 and L2 that make that vector perpendicular to both lines L1 and L2. (The dot product of direction vectors is zero.) The distance between the points found is the shortest distance between the lines.

__

Let P be a point on L1. Then the parametric equation for P is ...

  P = (6t, 0, -t) . . . . . . origin + t × direction vector

Let Q be a point on L2. The direction vector for L2 is given by the difference between the given points. It is (4-1, 1-(-1), 6-1) = (3, 2, 5). Then the parametric equation for Q is ...

  Q = (3s+1, 2s-1, 5s+1) . . . . (1, -1, 1) + s × direction vector

The direction vector for PQ is ...

  Q -P = (3s+1-6t, 2s-1, 5s+1+t)

The dot product of this and the two lines' direction vectors will be zero:

  (3s+1-6t, 2s-1, 5s+1+t)·(6, 0, -1) = 0 = 13s -37t +5 . . . perpendicular to L1

  (3s+1-6t, 2s-1, 5s+1+t)·(3, 2, 5) = 0 = 38s -13t +6 . . . perpendicular to L2

The solution to these equations is ...

  s = -157/1237

  t = 112/1237

Then (Q-P) becomes (94, -1551, 564)/1237, and its length is ...

  |PQ| = √(94² +1551² +564²)/1237 ≈ 1.3363

The distance between the two lines is about 1.3363 units.

8 0
3 years ago
A hot air balloon is released at ground level and it rises into the air at a constant rate . after 5 second the height of the ba
LenaWriter [7]

Answer:It's d

Step-by-step explanation:

8 0
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