The area of a right angled triangle with sides of length 9cm, 12cm and 15cm in square centimeters is 54 sq cm.
The formula to calculate the area of a right triangle is given by:
Area of Right Triangle, A = (½) × b × h square units
Where, “b” is the base (adjacent side) and “h” is the height (perpendicular side). Hence, the area of the right triangle is the product of base and height and then divide the product by 2.
We know that the hypotenuse is the longest side. So, the area of a right angled triangle will be half of the product of the remaining two sides.
Given sides of the triangle:
a=9cm
b=12cm
c=15cm
From this we know that the hypotenuse is c. Are of the triangle will be obtained by the other two sides.
∴Area = 
x 9 x 12
= 54
Step-by-step explanation:
work is shown and pictured
The phenomena of hiding distribution characteristics in a system from applications and users is known as distribution transparency. Access transparency, location transparency are some examples.
<h3>Define the term (distribution) transparency?</h3>
Distributed databases have the attribute of distribution transparency, which keeps consumers from knowing the internal workings of the distribution.
- The DDBMS designer has the option of replicating table fragments, storing them at several locations, and fragmenting tables.
- There are numerous distribution methods. Systems that need a wide range of management systems to pinpoint the source of resources, a product, or a service delivery process from the end user.
- Typically, the distributor, seller, or producer is responsible for maintaining transparency to track the many points at which resources, goods, or services are delivered.
- Accounting supplied by any intermediary company in the product, service, or resource flow is, of course, the usual approach to determine the degrees of value added through distribution management.
Thus, access transparency, location transparency are some examples of the (distribution) transparency.
To know more about the transparency, here
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f(x) = (3x+5)/7
Step 1:
we write f(x) as y
y=(3x+5)/7
Step 2:
switch y by x and x by y
x=(3y+5)/7
Step 3:
solve for y,
x=(3y+5)/7
multiply both sides by 7
7x=3y+5
subtract 5 from left side
3y=7x-5
divide both sides by 3
y= (7x-5)/3
f⁻¹ (x) =(7x-5)/3
Elimination, Multiply the second equation by -1, then add the equations together.
