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Zolol [24]
3 years ago
14

.

Mathematics
1 answer:
Rainbow [258]3 years ago
6 0

All of them will be subset of real numbers.

Explanation? — Refer to the attached image.

________________________________

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The zeros of a function are the values of x x for which the function is equal to zero. Enter a number in each blank to make true
Anit [1.1K]

Answer:

1 or 5

Step-by-step explanation:

Given the function h(x)=(2x−2)(x−5)

The zeros of h(x) are the values of x for which h(x)=0

h(x)=(2x−2)(x−5)=0

Note that if a.b=0, either a=0 or b=0.

Appying the above,

If (2x−2)(x−5)=0

Then:

2x−2=0 or x-5=0

2x=2 or x=5

x=1 0r 5

The zeroes of h(x) as defined are 1 or 5.

8 0
3 years ago
Llana ran 2 laps around the field in 8 minutes. what was he average speed
son4ous [18]

Answer: 1 Lap Per Every 4 Minutes Is Her Average Speed.

Step-by-step explanation: To find her average speed, simply divide 8 by 2 which is 4.

8/2 = 4 minutes per lap.

3 0
3 years ago
45 + 57 = x + y<br> x= 37<br> y =?
Mekhanik [1.2K]

Answer:

y = 65

Step-by-step explanation:

45 + 57 = x + y

x = 37

45 + 57 = 37 + y

45 + 57 = 102

102 = 37 + y

102 = 37 + y

-37    -37

102 - 37 = 65

37 + y - 37 = y

65 = y

y = 65

5 0
3 years ago
Read 2 more answers
A fudge recipe calls for 2 1/3 cups of flour for every 3/4 cups of cocoa powder. Could you increase the recipe proportionately b
ryzh [129]

same as before, is the proportion of one, the same as the other?  let's do the same here without much fuss.


\bf \stackrel{mixed}{2\frac{1}{3}}\implies \cfrac{2\cdot 3+1}{3}\implies \stackrel{improper}{\cfrac{7}{3}}&#10;~\hfill&#10;\stackrel{mixed}{4\frac{2}{3}}\implies \cfrac{4\cdot 3+2}{3}\implies \stackrel{improper}{\cfrac{14}{3}}


\bf \stackrel{mixed}{1\frac{1}{2}}\implies \cfrac{1\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{3}{2}}&#10;\\\\[-0.35em]&#10;\rule{34em}{0.25pt}\\\\&#10;\cfrac{~~2\frac{1}{3}~~}{\frac{3}{4}}=\cfrac{~~4\frac{2}{3}~~}{1\frac{1}{2}}\implies \cfrac{~~\frac{7}{3}~~}{\frac{3}{4}}=\cfrac{~~\frac{14}{3}~~}{\frac{3}{2}}\implies \cfrac{7}{3}\cdot \cfrac{4}{3}=\cfrac{14}{3}\cdot \cfrac{2}{3}\implies \cfrac{28}{9}=\cfrac{28}{9}~~\textit{\Large \checkmark}

4 0
3 years ago
Solve for each system of equations by substitution or elimination.
Tems11 [23]

QUESTION 1

The given system of equations are:

y=x^2+5x+1

y=x^2+2x+1

We equate the two equations to get:

x^2+5x+1 =x^2+2x+1

x^2 -  {x}^{2} + 5x  - 2x = 1 - 1

3x = 0

x = 0

When x=0,

y=0^2+2(0)+1 = 1

The solution is (0,1)

QUESTION 2

The given equations are:

y=x^2-2x - 1

and

y= -x^2-2x-1

We equate both equations to get:

x^2-2x - 1 = -x^2-2x-1

Group similar terms,

x^2 +  {x}^{2} -2x  + 2x= -1 + 1

2 {x}^{2}  = 0

x = 0

We put x=0 into any of the equations to find y.

y= -0^2-2(0)-1 =  - 1

The solution is (0,-1).

QUESTION 3

The given equations are:

y=x^2+2x+1

and

y=x^2+2x-1

We equate both equations:

x^2+2x+1 = x^2+2x-1

Group similar terms:

x^2 -x^2+2x = -1 - 1

0 =  -2

This is not true.

Hence the system has no solution.

6 0
3 years ago
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