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3 years ago

What's the answer Or I need some help

Mathematics

2 answers:

Yuliya22 [10]3 years ago

5 0

All you need to do is find a common denominator

5/1 = 25/5
2/5

25/5 - 2/5 = 23/5

turn into mixed number

4 3/5 is your answer

Pani-rosa [81]3 years ago

3 0

The answer is is 4 and 3/5

You might be interested in

Which expression represents the measure of segment rs? 7x – 3 7x 5 x 5 x – 3

inn [45]

Answer:

the answer is RS=x+5

if I am right mark it as brianliest

3 0

2 years ago

2. Find the measure of angle A to the nearest degree.

pav-90 [236]

Answer:

37°

Step-by-step explanation:

we're going to use cosine rule In calculating for the value of angle A

note that cosine rule can be used when two sides are given with an included angle . from the diagram above, the two sides given are side AB and side AC and the included angle is A

Hence cosine rule

a^2 = AB^2+AC^2 - 2AB×AC Cos A

3.2^2= 2.1^2+4.6^2-2×2.1×4.6COSA

10.24 =4.41+21.16- 19.32 COSA

10.24 = 25.57-19.32COSA

10.24-25.57= -19.32COSA

-15.33= -19.32COSA

dividing bothsides by - 19.32

COSA= -15.33/19.32

COA= 0.79347826

A = COS^-1 (0.79347826)

A= 37.488

A= 37°

<h2>hope this helps!!</h2>

7 0

2 years ago

YOOO PLEASE HELPPPP!!!!

Evgesh-ka [11]

Given:

Base length of triangle = 40 units

Height of triangle = 9 units

Length of hypotenuse of triangle = 41 units

To find:

Find the value of Tan A

Steps:

Tan of an angle is equal to the opposite length by adjacent length.

So,

Tan A = $\frac{opposite}{adjacent}$

Tan A = $\frac{9}{40}$

Tan A = 0.225

Therefore, the exact value of Tan A is 0.225.

Happy to help :)

If you need any help, feel free to ask

4 0

3 years ago

Suppose we have an unfair coin that its head is twice as likely to occur as its tail. a)If the coin is flipped 3 times, what is

Alenkinab [10]

Answer: a) 0.2222, b) 0.3292, c) 0.1111

Step-by-step explanation:

Since we have given that

Let the probability of getting head be p.

Since, its head is twice as likely to occur as its tail.

$p+\dfrac{p}{2}=1\\\\\dfrac{3p}{2}=1\\\\p=\dfrac{2}{3}$

a)If the coin is flipped 3 times, what is the probability of getting exactly 1 head?

So, here, n = 3

$p=\dfrac{2}{3}$

$q=\dfrac{1}{3}$

Now,

$P(X=1)=^3C_1(\dfrac{2}{3})^1(\dfrac{1}{3})^2=0.2222$

b)If the coin is flipped 5 times, what is the probability of getting exactly 2 tails?

2 tails means 3 heads.

So, it becomes,

$P(X=3)=^5C_3(\dfrac{2}{3})^3(\dfrac{1}{3})^2=0.3292$

c)If the coin is flipped 4 times, what is the probability of getting at least 3 tails?

$P(X\leq 1)=\sum _{x=0}^1^4C_x(\dfrac{2}{3}^x(\dfrac{1}{3})^{4-x}=0.1111$

Hence, a) 0.2222, b) 0.3292, c) 0.1111

8 0

3 years ago

In a secondary school there are 40 classes altogether.

fgiga [73]

So it would be 8/40. And in its simplest terms would be 1/5

7 0

3 years ago