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2 years ago

Order the decimales from leaste to gratest: 72.5, 73.943, 72.1, 73.77,

Mathematics

1 answer:

Sveta_85 [38]2 years ago

4 0

The decimals would be ordered as:

72.1, 72.5, 73.77, 73.943

42.1, 42.59, 43.2, 43.219

28.23, 38.4, 38.507, 38.507, 39.5

71.3, 71.3, 71.743, 72.43, 72.5

<h3>How to Order Decimals?</h3>

To order decimals from the least to the greatest, first state the lowest value, then progress to the highest taking account of the figures that come immediately after each decimal point.

The decimals will be ordered as shown below:

72.1, 72.5, 73.77, 73.943

42.1, 42.59, 43.2, 43.219

28.23, 38.4, 38.507, 38.507, 39.5

71.3, 71.3, 71.743, 72.43, 72.5

Learn more about ordering decimals on:

brainly.com/question/20603315

#SPJ1

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John decides to reduce a shape one half of its original size. The square that he had originally is 4 x 4. He reduces it so it will be 2×2

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Answer:

c. $\frac{1}{2 \sqrt{7} }$

Step-by-step explanation:

When plugging in zero into the given equation:

$\lim_{x \rightarrow 0} \frac{\sqrt{x + 7} - \sqrt{7} }{x} = \frac{0}{0}$

Answer is in indeterminate form = use L'Hospital's Rule:

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$\lim_{x \rightarrow 0} \frac{ \frac{1}{2} (x + 7)^{ \frac{-1}{2}} - 0 }{1}$

Rearranged equation:

$\lim_{x \rightarrow 0} \frac{1}{2 \sqrt{x + 7} }$

Plug zero back into equation:

$\lim_{x \rightarrow 0} \frac{1}{2 \sqrt{x + 7} } = \frac{1}{2 \sqrt{0 + 7} } = \frac{1}{2 \sqrt{7} }$

Answer:

$\lim_{x \rightarrow 0} \frac{\sqrt{x + 7} - \sqrt{7} }{x} = \frac{1}{2 \sqrt{7} }$

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3 years ago

Arrange the following from least to greatest 0.08,0.1, 1.8, 0.049, 0.103

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0.049, 0.08, 0.1, 0.103, 1.8.

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3 years ago

Ingrid mixes 3.6 pounds of almonds with some raisins to make a trail mix. She divides the trail mix into 12 equal portions. Each

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3 years ago

Read 2 more answers

A stereo store is offering a special price on a complete set ofcomponents (receiver, compact disc player, speakers, cassette dec

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Answer:

Step-by-step explanation:

(a)

The number of receivers is 5.

The number of CD players is 4.

The number of speakers is 3.

The number of cassettes is 4.

Select one receiver out of 5 receivers in $5C_1$ ways.

Select one CD player out of 4 CD players in $4C_1$ ways.

Select one speaker out of 3 speakers in $3C_1$ ways.

Select one cassette out of 4 cassettes in $4C_1$ ways.

Find the number of ways can one component of each type be selected.

By the multiplication rule, the number of possible ways can one component of each type be selected is,

The number of ways can one component of each type be selected is

$=5C_1*4C_1*3C_1*4C_1\\\\=5*4*3*4\\\\=240$

Part a

Therefore, the number of possible ways can one component of each type be selected is 240.

(b)

The number of Sony receivers is 1.

The number of Sony CD players is 1.

The number of speakers is 3.

The number of cassettes is 4.

Select one Sony receiver out of 1 Sony receivers in ways.

Select one Sony CD player out of 1 Sony CD players in ways.

Select one speaker out of 3 speakers in ways.

Select one cassette out of 4 cassettes in $4C_1$ ways.

Find the number of ways can components be selected if both the receiver and the CD player are to be Sony.

By the multiplication rule, the number of possible ways can components be selected if both the receiver and the CD player are to be Sony is,

Number of ways can one components of each type be selected

$=1C_1*1C_1*3C_1*4C_1\\\\=1*1*3*4\\\\=12$

Therefore, the number of possible ways can components be selected if both the receiver and the CD player are to be Sony is 12.

(c)

The number of receivers without Sony is 4.

The number of CD players without Sony is 3.

The number of speakers without Sony is 3.

The number of cassettes without Sony is 3.

Select one receiver out of 4 receivers in 4C_1 ways.

Select one CD player out of 3 CD players in 3C_1 ways.

Select one speaker out of 3 speakers in 3C_1 ways.

Select one cassette out of 3 cassettes in 3C_1 ways.

Find the number of ways can components be selected if none is to be Sony.

By the multiplication rule, the number of ways can components be selected if none is to be Sony is,

$=4C_1*3C_1*3C_1*3C_1\\\\=108$

[excluding sony from each of the component]

Therefore, the number of ways can components be selected if none is to be Sony is 108.

(d)

The number of ways can a selection be made if at least one Sony component is to be included is,

= Total possible selections -Total possible selections without Sony

= 240-108

= 132

Therefore, the number of ways can a selection be made if at least one Sony component is to be included is 132.

(e)

If someone flips the switches on the selection in a completely random fashion, the probability that the system selected contains at least one Sony component is,

$= \text {Total possible selections with at least one Sony} /\text {Total possible selections}$

= 132 / 240

= 0.55

The probability that the system selected contains exactly one Sony component is,

$= \text {Total possible selections with exactly one Sony} /\text {Total possible selections}$ $\frac{1C_1*3C_1*3C_1*3C_1+4C_11C_13C_13C_1+4C_13C_13C_13C_1}{240} \\\\=\frac{99}{240} \\\\=0.4125$

Therefore, if someone flips the switches on the selection in a completely random fashion, then is the probability that the system selected contains at least one Sony component is 0.55.

If someone flips the switches on the selection in a completely random fashion, then is the probability that the system selected contains exactly one Sony component is 0.4125.

6 0

3 years ago