Y = 2x - 3 . . . (1)
y = -2x + 5 . . . (2)
Equating (1) and (2),
2x - 3 = -2x + 5
2x + 2x = 5 + 3
4x = 8
x = 8/4 = 2
x = 2
y = 2(2) - 3 = 4 - 3 = 1
y = 1
Solution = (2, 1)
10u + t is the expressions shows the value of the reversal of digits in a two digit number, t = the tens digit and u = the ones digit. This can be obtained by multiplying 10 with the tens digit and adding unit digit.
<h3>Which is the required expressions?</h3>
Given that, in a two digit number,
t = the tens digit
u = the ones digit
The expression for the digit will be ,
10×t + u = 10t + u
The value of its reversal,
u = the tens digit
t = the ones digit
10×u + t = 10u + t is the required expression
For example,
37 = 10×3 + 7 = 30 + 7 and its reverse 73 = 10×7 + 3 = 70 + 3
Hence 10u + t is the expressions shows the value of the reversal of digits in a two digit number, t = the tens digit and u = the ones digit.
Learn more about algebraic expressions here:
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Answer:
C. 2^x+1
Step-by-step explanation:
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