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Nataliya [291]
3 years ago
8

TIME REMAINING

Mathematics
1 answer:
fiasKO [112]3 years ago
5 0
I think answer is 20 please give me brainlest I hope this helps thanks I appreciate it
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<img src="https://tex.z-dn.net/?f=54x2y%20-%2012x2y2" id="TexFormula1" title="54x2y - 12x2y2" alt="54x2y - 12x2y2" align="absmid
Free_Kalibri [48]

Answer:

6x²y(9 - 2y)

Step-by-step explanation:

Step 1: Factor out GCF

6(9x²y - 2x²y²)

Step 2: Factor out <em>x²</em>

6x²(9y - 2y²)

Step 3: Factor out <em>y</em>

6x²y(9 - 2y)

And we have our factored answer.

7 0
3 years ago
Read 2 more answers
Pls help its due today
Simora [160]

Answer:

the answer is a, unchecked growth

5 0
3 years ago
Read 2 more answers
A = 32°, a = 19, b = 14<br><br> solve the triangle using the law of cos
Lesechka [4]
Here is your solution.. hope it helps

6 0
3 years ago
Read 2 more answers
A wildlife audit was recently conducted in Port Augusta, the results of which were as follows: Amphibians Insects Fish Reptiles
r-ruslan [8.4K]

Answer:

The relative frequency of mammals in the survey is 30%.

Step-by-step explanation:

Relative frequency is the ratio of the occurrence of a singular event and the total number of outcome

Amphibians  Insects  Fish  Reptiles  Birds  Mammals

12                 30          9          25        22        42

Relative frequency = = \frac{\text{ (number of trials that are successful)}}{\text{(total number of trials)}}

Total number of wildlife animals  = 12+ 30 +9 +25+22+42 = 140

Now the relative frequency of mammals in the survey = \frac{\text{total number of mammals}}{\text{ Total number of animals}}

the relative frequency of mammals in the survey =\frac{42}{140} = 0.3

Converting into percentage , we get

=0.3 \times 100

= 30 %

5 0
3 years ago
Can you measure a time interval of 7 minutes using two sandglasses of 5 and 8 min each? If so, how?
Misha Larkins [42]

It can be done.

You must take a few steps to set it up, but then you are able to count 7 minutes. The setup makes you be able to time 2 minutes on the 5-minute sandglass and then you do another 5 minutes on the same sandglass.

Setup:

Start both sandglasses at the same time. When the 5-minute sandglass runs out, the 8 minute sandglass has 3 minutes of sand left. At this moment, start the 5 minute sandglass again.

When the 8-minute sandglass finishes the remaining 3 minutes, the 5-minute sandglass has 2 minutes left.

Actual timing of 7 minutes:

Let the 2 minutes pass, and immediately turn over the 5-minute sandglass to count an addition 5 minutes. The last 2 minutes of the 5-minute sandglass plus an additional 5 minutes of the 5-minute sandglass add to 7 minutes.

5 0
3 years ago
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