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3 years ago

Write a recursive formula for the sequence 7, 28, 112, 448, ... what is the formula for these?

Mathematics

1 answer:

liberstina [14]3 years ago

3 0

Answer:

true for all I know

Step-by-step explanation:

,.xxhxhxhxhhchxxjjxjxjxxjjxjxux

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A circle has center (0,4) and the same radius as the

kogti [31]

Answer:

x² + (y - 4)² = 25

Step-by-step explanation:

you didn't list any equation

Here's one possible answer

x² + (y - 4)² = 25

7 0

3 years ago

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The ratio of boys to girls is 14:17 if there are a total of 7626 students how many boys and how many girls are there ?

Finger [1]

Answer: 3444 boys, 4182 girls

Let there be 14x boys and 17x girls. Then there are 31x total students. Since 31x = 7626, x = 246. Then there are 14(246) = 3444 boys and 17(246) = 4182 girls.

i hope this was helpful! :D

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3 years ago

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What type of transformation is shown?

Ilya [14]

I believe it is a reflection?

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3 years ago

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I had $13.00. My mom gave $10.00 my dad gave $30. My Aunt, My uncle and grandma gave me $100. I had another $7.00. How much did

Rina8888 [55]

$160 (if uncle, granny, aunt, gave $100 in total) $260 if they gave $100 each

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3 years ago

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I need Help with calculus please, thank you! 10points

natta225 [31]

3) We have

$f(x) = \sec\left(\dfrac{\pi x}2\right) = \dfrac1{\cos\left(\frac{\pi x}2\right)}$

which has vertical asymptotes (i.e. infinite discontinuities) whenever the denominator is zero. This happens for

$\cos\left(\dfrac{\pi x}2\right) = 0$

$\implies \dfrac{\pi x}2 = \cos^{-1}(0) + 2n\pi \text{ or } \dfrac{\pi x}2 = -\cos^{-1}(0) + 2n\pi$

(where $n$ is any integer)

$\implies \dfrac{\pi x}2 = \dfrac\pi2 + 2n\pi \text{ or } \dfrac{\pi x}2 = -\dfrac\pi2 + 2n\pi$

$\implies x = 1 + 4n \text{ or } x = -1 + 4n$

So the graph of $f(x)$ has vertical asymptotes whenever $x=4n\pm1$ and $n\in\Bbb Z$ .

4) Given

$h(t) = \begin{cases} t^3+1 & \text{if } t$

we have the one-sided limits

$\displaystyle \lim_{t\to1^-} h(t) = \lim_{t\to1} (t^3+1) = 1^3+1 = 2$

and

$\displaystyle \lim_{t\to1^+} h(t) = \lim_{h\to1} \frac{t+1}2 = \frac{1+1}2 = 1$

The one-sided limits don't match, so the two-sided limit $L$ does not exist. In other words, the limit does not exist at $x=1$ because the function approaches different values from the left and right side of $x=1$ .

6 0

2 years ago