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3 years ago

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Holland added three decimals that made a sum of 2. One of the decimals was 0.34. What are two other decimals Holland could have

used to make a sum of 2

2 answers:

bogdanovich [222]3 years ago

7 0

Using x to represent our missing values and the fact that there are two missing values gives us x + x = 2x. Because it's the sum of these numbers and 0.34, we get the equation 2x + 0.34; now we set it equal to 2, 2x + 0.34 = 2.

To solve, 1st subtract 0.34 on both sides to get 2x = 1.66. Now divide by 2 on both sides to get x = 0.83.

So your decimals are 0.34, 0.83, and 0.83

melamori03 [73]3 years ago

3 0

Answer:

In general the two other decimals are x and y that satisfy x + y = 1.66 where x ≤ .99 and y ≤ .99

One particular pair would be x = 0.99 and y = 0.67

Step-by-step explanation:

If Holland added three decimals that made a sum of 2 and one of them was 0.34, we are going to name x and y to the other 2 decimals.

We are going to write the equation:

$0.34 + x +y= 2\\x+y=2-0.34\\x+y = 1.66$

So we have that both the other numbers have to sum 1.66, however, we know both numbers are decimals so neither one of them can be greater than 1.

So this problem has many answers and the answers would be all the numbers that satisfy x + y = 1.66 where x ≤ .99 and y ≤ .99

For example, if x = 0.99, y would be:

y = 1.66 -0.99 = 0.67.

And our pair of numbers would be 0.99 and 0.67.

If x = .80, y would be

y = 1.66 - 0.80 = 0.86

And our pair of numbers would be 0.80 and 0.86

This way, we can find more than 1 answer for the other two decimals.

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2 years ago

In Applied Life Data Analysis (Wiley, 1982), Wayne Nelson presents the breakdown time of an insulating fluid between electrodes

ale4655 [162]

Answer:

The sample mean is $\bar{x}=14.371$ min.

The sample standard deviation is $\sigma = 18.889$ min.

Step-by-step explanation:

We have the following data set:

$\begin{array}{cccccccc}0.15&0.82&0.81&1.44&2.70&3.28&4.00&4.70\\4.96&6.49&7.25&8.03&8.40&12.15&31.89&32.47\\33.79&36.80&72.92&&&&&\end{array}$

The mean of a data set is commonly known as the average. You find the mean by taking the sum of all the data values and dividing that sum by the total number of data values.

The formula for the mean of a sample is

$\bar{x} = \frac{{\sum}x}{n}$

where, $n$ is the number of values in the data set.

$\bar{x}=\frac{0.15+0.82+0.81+1.44+2.7+3.28+4+4.7+4.96+6.49+7.25+8.03+8.4+12.15+31.89+32.47+33.79+36.80+72.92}{19}\\\\\bar{x}=14.371$

The standard deviation measures how close the set of data is to the mean value of the data set. If data set have high standard deviation than the values are spread out very much. If data set have small standard deviation the data points are very close to the mean.

To find standard deviation we use the following formula

$\sigma = \sqrt{ \frac{ \sum{\left(x_i - \overline{x}\right)^2 }}{n-1} }$

The mean of a sample is $\bar{x}=14.371$ .

Create the below table.

Find the sum of numbers in the last column to get.

$\sum{\left(x_i - \overline{X}\right)^2} = 6422.0982$

$\sigma = \sqrt{ \frac{ \sum{\left(x_i - \overline{x}\right)^2 }}{n-1} } = \sqrt{ \frac{ 6422.0982 }{ 19 - 1} } \approx 18.889$

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Svetach [21]

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Kisachek [45]

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4 years ago

Read 2 more answers

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vladimir1956 [14]

Answer:

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Step-by-step explanation:

1) Rewrite the problem as an equation: (x will be "a number")

9x+6=456

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3) Divide both sides by 9:

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3 years ago