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lidiya [134]
3 years ago
14

Find integer solutions for the equation 620 p+140w= 20 .

Mathematics
1 answer:
Nutka1998 [239]3 years ago
6 0
Im not sure, maybe determined answer B
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2x=8 <br>so find the value of x​
melisa1 [442]

Answer:

x = 4

Step-by-step explanation:

2x/2 = 8/2

x =4

6 0
3 years ago
WILL GIVE BRAINLLEST
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7idjdjdbrhzuzhhwbscjcjc
3 0
3 years ago
How to solve for 6x-12+2x=3+8x-15
Alecsey [184]
6x−12+2x=3+8x−15

Simplify:

6x+−12+2x=3+8x+−15

(6x+2x)+(−12)=(8x)+(3+−15)(Combine Like Terms)

8x+−12=8x+−12


8x−12=8x−12

Subtract 8x from both sides.

8x−12−8x=8x−12−8x

−12=−12

Add 12 to both sides.

−12+12=−12+12

0=0

The real numbers are the only solution we can have.


4 0
3 years ago
Using the information in the table, which animal shelter shows that exactly 42% of the total animals are cats? 100 out of 160 42
arlik [135]
Jejsjsjsjdididididirieie 63 is correct answer
6 0
3 years ago
One uranium atom has a mass of 3.95 x 10^-22 grams.
creativ13 [48]
Remember
(ab)/(cd)=(a/c)(b/d)
and
\frac{x^n}{x^m}=x^{n-m}

1kg=1000g=1*10^3g
hmm, I estimate, 4 of them

x=number of attoms
mass of 1 times x=1*10^3
3.95*10^-22 times x=1*10^3
divide both sides by 3.95*10^-22
x=\frac{1*10^3}{3.95*10^{-22}}= (\frac{1}{3.95}  )( \frac{10^{3}}{10^{-22}} )=0.25316*10^{25}=2.5316*10^{24}
a million has 9 zeroes
so 24 zeroes is alot that is a <span>septillion, so there are 2.5316 septillion uranium atoms in 1kg


a. 4
b. underestimate

</span>
5 0
3 years ago
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