Answer:
The probability that sample mean differ the true greater than 2.1 will be 2.8070 %
Step-by-step explanation:
Given:
Sample mean =46 dollars
standard deviation=8
n=53
To Find :
Probability that sample mean would differ from true mean by greater than 2.1
Solution;
<em>This sample distribution mean problem,</em>
so for that
calculate Z- value
Z=(sample mean - true mean)/(standard deviation/Sqrt(n))
Z=-2.1/(8/Sqrt(53))
Z=-2.1*Sqrt(53)/8
Z=-1.91102
Now for P(X≥2.1)=P(Z≥-1.91102)
Using Z-table,
For Z=-1.91
P(X>2.1)=0.02807
Answer:
the last one bottom right
Step-by-step explanation:
well, did it in my head, but the idea is to calculate it out
(x-8)*(x-8)=50
is just
x²-16x+64=50
to get the 64 down to just 5, we need to subtract 59, on both sides, leaving us with -9 on the righthand side
She would spend $35.00 on each jacket. Just multiply
Answer:
I believe it's the 3rd awnser