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Expand using the Binomial Theorem (3x+2)^4
(3x+2)4(3x+2)4
Use the binomial expansion theorem to find each term. The binomial theorem states (a+b)n=n∑k=0nCk⋅(an−kbk)(a+b)n=∑k=0nnCk⋅(an-kbk).
4∑k=04!(4−k)!k!⋅(3x)4−k⋅(2)k∑k=044!(4-k)!k!⋅(3x)4-k⋅(2)k
Expand the summation.
4!(4−0)!0!⋅(3x)4−0⋅(2)0+4!(4−1)!1!⋅(3x)4−1⋅(2)+4!(4−2)!2!⋅(3x)4−2⋅(2)2+4!(4−3)!3!⋅(3x)4−3⋅(2)3+4!(4−4)!4!⋅(3x)4−4⋅(2)44!(4-0)!0!⋅(3x)4-0⋅(2)0+4!(4-1)!1!⋅(3x)4-1⋅(2)+4!(4-2)!2!⋅(3x)4-2⋅(2)2+4!(4-3)!3!⋅(3x)4-3⋅(2)3+4!(4-4)!4!⋅(3x)4-4⋅(2)4
Simplify the exponents for each term of the expansion.
1⋅(3x)4⋅(2)0+4
Hope this helps!
Answer:
b. would be the answer bc it goes in a line if you were to connect the dots

- Given - <u>an </u><u>equation</u><u> </u><u>in </u><u>a </u><u>standard</u><u> </u><u>form</u>
- To do - <u>simplify</u><u> </u><u>the </u><u>equation</u><u> </u><u>so </u><u>as </u><u>to </u><u>obtain </u><u>an </u><u>easier </u><u>one</u>
<u>Since </u><u>the </u><u>equation</u><u> </u><u>provided </u><u>isn't</u><u> </u><u>i</u><u>n</u><u> </u><u>it's</u><u> </u><u>general</u><u> </u><u>form </u><u>,</u><u> </u><u>let's</u><u> </u><u>first </u><u>convert </u><u>it </u><u>~</u>
<u>General</u><u> </u><u>form </u><u>of </u><u>a </u><u>Linear</u><u> equation</u><u> </u><u>-</u>

<u>T</u><u>he </u><u>equation</u><u> </u><u>after </u><u>getting</u><u> </u><u>converted</u><u> </u><u>will </u><u>be </u><u>as </u><u>follows</u><u> </u><u>~</u>

hope helpful ~
Answer:
422mins and 8sec
Step-by-step explanation:
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