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3 years ago

HELP ME FAST I WILL GIVE POINTS!!

Mathematics

2 answers:

coldgirl [10]3 years ago

6 0

Answer:

Step-by-step explanation:

Where is the link?

Margaret [11]3 years ago

3 0

Answer:

wheres the question then ill try n help

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Give the discriminant of the equation 0 = −x2+6x−9 please answer

Brut [27]

Answer:

x = 3

Steps:

$- ( {x}^{2} - 6x + 9) = 0$

$- {(x - 3)}^{2} = 0$

${(x - 3)}^{2} = 0$

$x - 3 = 0$

There you go!

8 0

3 years ago

What is the answer.

Alenkasestr [34]

√11 √5 = √(11 * 5) = √55 = approx 7.42 (rounded)

4 0

3 years ago

There are 56 trees in an apple orchard. They are arranged in equal rows. There are 8 trees in each row. How many rows of apple t

Amiraneli [1.4K]

56 ÷8=7

Hope it helped

8 0

3 years ago

Read 2 more answers

Use l'Hôpital's Rule to find the following limit. ModifyingBelow lim With x right arrow 0StartFraction 3 sine (x )minus 3 x Ove

steposvetlana [31]

Answer:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=-\frac{1}{14}$

Step-by-step explanation:

The limit is:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{0}{0}$

so, you have an indeterminate result. By using the l'Hôpital's rule you have:

$\lim_{x \to 0} \frac{a(x)}{b(x)}= \lim_{x \to 0} \frac{a'(x)}{b'(x)}$

by replacing, and applying repeatedly you obtain:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}= \lim_{x \to 0}\frac{3cosx-3}{21x^2}= \lim_{x \to 0}\frac{-3sinx}{42x}= \lim_{x \to 0}\frac{-3cosx}{42}\\\\ \lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{-3cos0}{42}=-\frac{1}{14}$

hence, the limit of the function is -1/14

8 0

3 years ago

3. Write an equation parallel to the line y = 2x – 2 which goes through (0,3)

solmaris [256]

Answer:

Ok y= 2x + b

b referring to any number less than -2 and more than -2

so y=2x+4 can work

Step-by-step explanation:

parallel lines in slope-intercept form have the same slope, i.e. the same 'm' value or coefficient of x but different interceptions

4 0

3 years ago