Log9 =2
3
because logz =y when x^y = z
x
Solve for x.
x > 3
(It goes to the right, with the starting point open)
Answer:
0.50 kg of the material would be left after 10 days.
0.25 kg of the material would be left after 20 days.
Step-by-step explanation:
We have been given that the half-life of a material is 10 days. You have one 1 kg of the material today. We are asked to find the amount of material left after 10 days and 20 days, respectively.
We will use half life formula.
, where,
A = Amount left after t units of time,
a = Initial amount,
t = Time,
h = Half-life.




Therefore, amount of the material left after 10 days would be 0.5 kg.





Therefore, amount of the material left after 20 days would be 0.25 kg.
Answer:
Horizontal Asymptote: y=2
Vertical Asymptote: x=3
Step-by-step explanation:
One way: Look at graph
Look at for a horizontal or vertical line that both lines don't touch.
Second Way:
When you look for vertical asymptotes, you set the denominator equal to zero and solve.
For example, the second question has a denominator of x-3.
x-3=0
x=3 (This is the vertical asymptote)
When you look for horizontal asymptote, you do long division.
For example, the first question 
The answer will be 2. 2 is the quotient. You only want quotient not remainder.
y=2.
Answer:
Erm i dont see anything here.
Step-by-step explanation: