Let the number of nickels be = x
Let the number of dimes be = d
Let the number of quarter be = n
Given is, she has twice as many dimes as quarters
d=2n or n = 0.5d
She has two less quarters than nickles.
n= x-2 or
x= n+2
Total values of coins is = $2.60
Now replace x with (n+2) and d with 2n
Now x=n+2 ; x=5+2 = 7
d=2n ; d=2(5) = 10
Hence, Elina has 7 nickels, 10 dimes and 5 quarters.
Answer:
you taking that end of module assessment too?
Step-by-step explanation:
Answer:
130 inches
Step-by-step explanation:
Area = Length · Width
Solve for the Right Triangle
6 · 11 = 66 inches
Area = Length · Width
Solve for the square
Since the width isn't fully given, we must add 5 + 3 = 8 inches
5 · 8 = 40 inches
Area = Length · Width
Solve for the Rectangle
8 · 3 = 24 inches
Now add the results: 66 + 40 + 24 = 130 in^2
x*5 - quarter amount
(x+15)*25- nickels amount
(x*5)+((x+15)*25)=735
5x+25x+375=735
30x=735-375
30x=360
x=360/30=12 - number of nickels
x+15=12+15=27 - number of quarters
CHECK
12*5=60 ¢
27*25=675 ¢
675+60=735 ¢ or $7.35
