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4 years ago

What is the surface area of a cube that has sides 4 cm long?

Mathematics

1 answer:

Yuki888 [10]4 years ago

6 0

Answer:

96cm²

Step-by-step explanation:

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X=2y-6 y=-3x+17 solve for substitution

Kitty [74]

The answer to this is y= 5.

3 0

3 years ago

Find (a) the number of subsets and (b) the number of proper subsets of the set.

vaieri [72.5K]

Answer:

(a) Total No. of Subsets = 128

(b) Total No. of Proper Subsets = 127

Step-by-step explanation:

First we need to define the set of days of the week.

Set of Days of Week = {Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday}

It is evident from the set of days of the week, that it contains 7 elements.

(a)

The total no. of subsets of a given set is given by the following formula:

Total No. of Subsets = 2^n

where,

n = no. of elements of the set = 7

Therefore,

Total No. of Subsets = 2^n

Total No. of Subsets = 2^7

Total No. of Subsets = 128

(b)

The total no. of proper subsets of a given set is given by the following formula:

Total No. of Proper Subsets = (2^n) - 1

where,

n = no. of elements of the set = 7

Therefore,

Total No. of Proper Subsets = (2^n) - 1

Total No. of Proper Subsets = (2^7) - 1 = 128 - 1

Total No. of Proper Subsets = 127

3 0

3 years ago

Suppose a circle has a varying radius of r inches and a square has a varying side length of s inches. Let D represent how much g

tamaranim1 [39]

Answer:

Step-by-step explanation:

8 0

4 years ago

I need help with this plz help me fast!!

lesya692 [45]

The answer is A I believe

4 0

3 years ago

Read 2 more answers

Select the correct answer from each drop-down menu.

podryga [215]

Answer with explanation:

$\text{Average}=\frac{\text{Sum of all the observation}}{\text{Total number of Observation}}$

Average Height of tallest Building in San Francisco

$=\frac{260+237+212+197+184+183+183+175+174+173}{10}\\\\=\frac{1978}{10}\\\\=197.8$

Average Height of tallest Building in Los Angeles

$=\frac{310+262+229+228+224+221+220+219+213+213}{10}\\\\=\frac{2339}{10}\\\\=233.9$

→→Difference between Height of tallest Building in Los Angeles and Height of tallest Building in San Francisco

=233.9-197.8

=36.1

⇒The average height of the 10 tallest buildings in Los Angeles is 36.1 more than the average height of the tallest buildings in San Francisco.

⇒Part B

Mean absolute deviation for the 10 tallest buildings in San Francisco

|260-197.8|=62.2

|237-197.8|=39.2

|212-197.8|=14.2

|197 -197.8|= 0.8

|184 -197.8|=13.8

|183-197.8|=14.8

|183-197.8|= 14.8

|175-197.8|=22.8

|174-197.8|=23.8

|173 -197.8|=24.8

Average of these numbers

$=\frac{62.2+39.2+14.2+0.8+13.8+14.8+14.8+22.8+23.8+24.8}{10}\\\\=\frac{231.2}{10}\\\\=23.12$

Mean absolute deviation=23.12

5 0

3 years ago