3 years ago

Please help :( im stuck!!

Mathematics

1 answer:

Ludmilka [50]3 years ago

5 0

Answer:

you taking that end of module assessment too?

Step-by-step explanation:

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The system of the equation doesn't give the solution at (-3, -6).

<h2>Given to us</h2>

-4x+y = 6
5x-y =21

<h3>Equation 1,</h3>

-4x+y = 6

solve for y

$-4x+y =6\\y= 6+4x$

<h3>Equation 2,</h3>

5x-y =21

substitute the value of y in equation 2,

$5x-(6+4x) =21\\5x -6 -4x =21\\5x -4x=21+6\\x = 27$

Substitute the value of x in equation 2,

$5x-y =21\\5(27)-y =21\\135-y = 21\\-y=21-135\\-y = -114\\y=114$

We can see that the solution of the two equations is at (27, 114). Also, it can be verified by plotting the line on the graph.

Hence, the system of the equation doesn't give the solution at (-3, -6).

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