3 years ago

Please help :( im stuck!!

Mathematics

1 answer:

Ludmilka [50]3 years ago

5 0

Answer:

you taking that end of module assessment too?

Step-by-step explanation:

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3 years ago

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3 years ago

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3 years ago

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I have k quarters, five less quarters than nickels and one more than twice as many dimes as quarters. Find the value of the coin

Alenkinab [10]

Answer:

(35k + 20) cents

Step-by-step explanation:

First of all, let us have the value of each unit:

1 quarter = 25 cents

1 nickel = 5 cents

1 dime = 10 cents

Given that number of quarter = k

Quarters are 5 lesser than Nickels, so number of nickels = k+5

One more than twice as many dimes as quarters:

k = 2 $\times$ Number of Dimes + 1

So, number of dimes = $\frac{1}{2}(k-1)$

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So, total value of coins =

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4 years ago

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