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bagirrra123 [75]
3 years ago
13

The Lamaster family is a family of five people. They have used 4,885.78 gallons of water so far this month. They cannot exceed 7

,250.50 gallons per month during drought season. Write an inequality to show how much water just one member of the family can use for the remainder of the month, assuming each family member uses the same amount of water every month.
5x − 4,885.78 ≤ 7,250.50
5x + 4,885.78 ≤ 7,250.50
5x − 4,885.78 ≥ 7,250.50
5x + 4,885.78 ≥ 7,250.50
Mathematics
1 answer:
oksian1 [2.3K]3 years ago
8 0

Let X be the amount of water one person can use.

Multiply that by 5 people to get 5X

That amount plus what they already used ( 4885.78) needs to be less than or equal to the amount they are limited to ( 7250.50 ).

Now write out the equation to get : 5x + 4885.78 ≤ 7250.50

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Answer:

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Step-by-step explanation:

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3 years ago
A Packaging Company produces boxes out of cardboard and has a specified weight of 16 oz. A random sample of 36 boxes yielded a s
user100 [1]

Answer:

The margin of error is of 0.73 oz.

The 99% confidence interval for the true mean weight of the boxes is between 14.57 oz and 16.03 oz. This means that we are 99% sure that the true mean weight of all boxed produced by the Packaging Company is between these two values, and that the specified weight is in this interval.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.99}{2} = 0.005

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That is z with a pvalue of 1 - 0.005 = 0.995, so Z = 2.575.

Now, find the margin of error M as such

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In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 2.575\frac{1.7}{\sqrt{36}} = 0.73

The margin of error is of 0.73 oz.

The lower end of the interval is the sample mean subtracted by M. So it is 15.3 - 0.73 = 14.57 oz.

The upper end of the interval is the sample mean added to M. So it is 15.3 + 0.73 = 16.03 oz.

The 99% confidence interval for the true mean weight of the boxes is between 14.57 oz and 16.03 oz. This means that we are 99% sure that the true mean weight of all boxed produced by the Packaging Company is between these two values, and that the specified weight is in this interval.

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3 years ago
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dlinn [17]
The answer to your question is <span>−10.8</span>
8 0
3 years ago
Read 2 more answers
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wel
Kelli ran 4 more miles than the week before, so to find what percent that is of 28, divide.

4 / 28 = 0.142857143, or ~14.29%

Kelli ran 14.2857143% or about 14.29% more miles than last week.
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4 years ago
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