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3 years ago

7 square root of 3 end root minus 4 square root of 6 end root plus square root of 48 end root minus square root of 54

1 answer:

5 0

$7\sqrt3-4\sqrt6+\sqrt{48}-\sqrt{54}\\\\=7\sqrt3-4\sqrt6+\sqrt{16\cdot3}-\sqrt{9\cdot6}\\\\=7\sqrt3-4\sqrt6+\sqrt{16}\cdot\sqrt3-\sqrt9\cdot\sqrt6\\\\=7\sqrt3-4\sqrt6+4\sqrt3-3\sqrt6\\\\=\boxed{11\sqrt3-7\sqrt6}$

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3 years ago

Determine the area of the triangular ABC with AC=5cm and height DB=30 mm.<br>

Lady_Fox [76]

Answer:

750 mm²

Step-by-step explanation:

<h3>Area of triangle:</h3>

To find the area of the triangle, multiply the base and height and then divide the result by 2.

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2 years ago

Find the median of 30 , 40, 35, 50 and 55 degrees angle measures

ELEN [110]

We know that
the median <span>is the middle number when listed in order from least to greatest.
</span>
step 1
listed in order from least to greatest
[<span>30,40, 35, 50, 55]--------> [30, 35, 40, 50, 55]

step 2
find the middle number

the middle number is 40

therefore

the answer is
the median is 40</span>°<span>

</span>

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3 years ago